Answer:
a) Platinum > Beryllium > Aluminum > Magnesium > Potassium > Cesium
b) Cesium > Potassium > Magnesium > Aluminum > Beryllium > Platinum
c) Cesium > Potassium
Explanation:
We must recall that the frequency of an electromagnetic wave is directly proportional to its energy. Hence as the work function of the metal increases, the minimum frequency required for emission of electrons occur increases accordingly.
Similarly, the maximum wavelength required for electron emission to occur varies inversely as the work function of the metal hence the answer provided.
Lastly, only caesium and potassium has work function less than the energy of the incident photon hence only these two metals experience electron emission with the kinetic energy of electrons emitted from caesium greater than that emitted from potassium.
Answer: mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm
Explanation:
Answer:
Molecular equation: NaCl(aq) + AgNO₃(aq) → NaNO₃(aq) + AgCl(s)↓
Net ionic equation: Cl⁻(aq) + Ag⁺(aq) → AgCl (s)
Explanation:
We determine the reactants for the reaction:
NaCl and AgNO₃
In aqueous solutions, salts from nitrate are soluble (all soluble)
In aqueous solutions, salts from chloride can make precipitate (with Ag⁺, Pb²⁺ Hg²⁺, Cu²⁺)
We dissociate the reactants:
NaCl → Na⁺ + Cl⁻
AgNO₃ → Ag⁺ + NO₃⁻
Molecular equation: NaCl(aq) + AgNO₃(aq) → NaNO₃(aq) + AgCl(s)↓
To build the net ionic equation we pick up the ions:
Na⁺(aq) + Cl⁻(aq) + Ag⁺(aq) + NO₃⁻(aq) → NO₃⁻(aq) + Na⁺(aq) + AgCl (s)
Those who are solid must be written as a compound, the ions are only from aq solutions. As we find NO₃⁻ and Na⁺ in both sides of the reactions we named them, spectators ions because they do not react. We can cancel them, so the net ionic equation is: Cl⁻(aq) + Ag⁺(aq) → AgCl (s)
Answer: genus
Explanation:
Amoebas do not form a single taxonomic group; instead, they are found in every major lineage of eukaryotic organisms. Amoeboid cells occur not only among the protozoa, but also in fungi, algae, and animals.