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White raven [17]
3 years ago
10

Write the molecular formula of sodium bicarbonate and write any two uses of it.

Chemistry
1 answer:
gulaghasi [49]3 years ago
5 0

\huge\mathcal\colorbox{cyan}{{\color{blue}{AnSwEr~↓~↓~}}}

\huge\mathbb\colorbox{black}{\color{white}{FORMULA\:\:↓}}

<h3><em>NaHCO3</em></h3>

\huge\mathbb\colorbox{black}{\color{white}{USES\:\:↓}}

<h3><em>preparing baking powder. as an antacid in medicine. in fire extinguishers. manufacture of soda water.</em></h3>

\huge \colorbox{pink}{Hope \: It \: Help \: U}

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In July 1994 the comet shoemaker-levy 9 collided with the planet Jupiter, as scientists had predicted. To be able to accurately
Korvikt [17]

Answer:

the gravitational attraction that exists between all bodies

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5 0
3 years ago
Can someone please help me finish this all?
Phoenix [80]

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4 0
3 years ago
Calculate the pH at the equivalence point for the titration of 0.110 M methylamine (CH3NH2) with 0.110 M HCl. The Kb of methylam
nikklg [1K]
The reaction between the reactants would be:

CH₃NH₂ + HCl ↔ CH₃NH₃⁺ + Cl⁻

Let the conjugate acid undergo hydrolysis. Then, apply the ICE approach.

             CH₃NH₃⁺ + H₂O → H₃O⁺ + CH₃NH₂
I                0.11                       0             0
C               -x                          +x           +x
E            0.11 - x                     x             x

Ka = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]

Since the given information is Kb, let's find Ka in terms of Kb.

Ka = Kw/Kb, where Kw = 10⁻¹⁴

So,
Ka = 10⁻¹⁴/5×10⁻⁴ = 2×10⁻¹¹ = [H₃O⁺][CH₃NH₂]/[CH₃NH₃⁺]
2×10⁻¹¹ = [x][x]/[0.11-x]
Solving for x,
x = 1.483×10⁻⁶ = [H₃O⁺]

Since pH = -log[H₃O⁺],
pH = -log(1.483×10⁻⁶)
<em>pH = 5.83</em>


4 0
3 years ago
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