Answer:
7% 4)2(10
Explanation:
beacouse if you divide it you can get the answer
Answer:
These two are equivalent and valid:


Explanation:
The molecular superscripts for each atom in the <em>molecular formula</em> are determined by the number of times that the mass of the<em> empirical formula</em> is contained in the<em> molar mass</em>.
<u />
<u>1. Determine the mass of the empirical formula:</u>
:
Atomic masses:
- O: 15.999g/mol
- C: 12.011g/mol
- N: 14.007g/mol
- Cl: 35.453g/mol
Total mass:
- 15.999g/mol + 12.011g/mol + 14.007g/mol + 35.453g/mol = 77.470g/mol
<u />
<u>2. Divide the molar mass by the mass of the empirical formula:</u>
- 232.41g/mol / 77.470g/mol = 3
<u>3. Multiply each superscript of the empirical formula by the previous quotient: 3</u>

Or:

You might also write CN as a group:

Answer:
The fractional saturation for hemoglobin is 0.86
Explanation:
The fractional saturation for hemoglobin can be calculated using the formula

Where
is the fractional oxygen saturation
is the partial pressure of oxygen
is the partial pressure when 50% hemoglobin is saturated with oxygen
and h is the Hill coefficient
From the question,
= 40 mm Hg
= 22 mm Hg
h = 3
Putting these values into the equation, we get





Hence, the fractional saturation for hemoglobin is 0.86.
% error = | accepted value - experimental value | / accepted value × 100
Step one- | 4.15mL - 4.26mL | = 0.11
Step two- 0.11 / 4.15 = 0.027
Step three- -0.027 × 100 = 2.7%
Answer:
Diverging plates from mountains
Correct me if wrong