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2 years ago

Both natural products and synthetic products come from natural resources. Explain why this statement is true.

Chemistry

1 answer:

xz_007 [3.2K]2 years ago

5 0

Explanation:

All resources used in making all products can be traced to their natural origin. What differentiates a natural product from a synthetic one is the level of processing that goes into making synthetic products.

For example, a synthetic product such as plastic is actually derived from natural product.
Instead of using the sap of rubber plants for making this product, scientists engineered a way to produce plastics from petroleum products which are derived from crude oil.
Most synthetic products are merely products of alternate source of manufacturing which are well engineered.

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If 175mL of oxygen is produced at STP, how many grams of hydrogen peroxide, H2O2

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Answer:

0.53g

Explanation:

We'll begin by converting 175mL to L. This is illustrated below:

1000mL = 1L

Therefore 175mL = 175/1000 = 0.175L

Next, we shall calculate the number of mole of O2 that occupy 0.175L. This is illustrated below:

1 mole of O2 occupy 22.4L at stp.

Therefore, Xmol of O2 will occupy 0.175L i.e

Xmol of O2 = 0.175/22.4

Xmol of O2 = 7.81×10¯³ mole

Therefore, 7.81×10¯³ mole of O2 occupy 175mL.

Next, we shall determine the number of mole of H2O2 that decomposed to produce 7.81×10¯³ mole of O2. This is illustrated below:

2H2O2 —> 2H2O + O2

From the balanced equation above,

2 moles of H2O2 decomposed to produce 1 mole of O2.

Therefore, Xmol of H2O2 will decompose to produce 7.81×10¯³ mole of O2 i.e

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Xmol of H2O2 = 1.562×10¯² mole

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Finally, we shall convert 1.562×10¯² mole of H2O2 to grams. This is illustrated below:

Molar mass of H2O2 = (2x1) + (16x2) = 34g/mol

Mole of H2O2 = 1.562×10¯² mole

Mass of H2O2 =..?

Mole = mass /Molar mass

1.562×10¯² = mass /34

Cross multiply

Mass of H2O2 = 1.562×10¯² x 34

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Therefore, 0.53g of Hydrogen peroxide, H2O2 were decomposition in the reaction.

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3 years ago

How many particles would be found in a 1.224 g sample of K2O

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Number of particles= 0.01654*6.0221409*10^23

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