Answer:
3.98 g
Explanation:
Step 1. Write the balanced chemical reaction. In this case, magnesium reacts with oxygen to produce magnesium oxide:
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Step 2. Calculate the number of moles of magnesium:
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Step 3. Calculate the number of moles of oxygen:
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Step 4. Identify the limiting reactant comparing the equivalents. Equivalent of Mg:
Equivalent of oxygen:
Therefore, Mg is the limiting reactant.
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Step 5. According to the stoichiometry of this reaction:
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Step 6. Convert the number of moles of MgO into mass:
The three particles found in an atom are the protons, neutrons and electrons. Protons have a positive charge. Electrons have negative charge. Lastly, neutrons have no net electrical charge. Protons and neutrons are much heavier than electrons and are located in the center of the atom.
The vertical columns on the periodic table are called groups or families<span> because of their similar chemical behavior. All the members of a </span>family<span> of </span>elements<span> have the</span>same<span> number of valence electrons and similar chemical properties</span>
Answer:
P₂ = 130.18 kPa
Explanation:
In this case, we need to apply the Gay-Lussack's law assuming that the volume of the container remains constant. If that's the case, then:
P₁/T₁ = P₂/T₂ (1)
From here, we can solve for the Pressure at 273 K:
P₂ = P₁ * T₂ / T₁ (2)
Now, all we need to do is replace the given data and solve for P₂:
P₂ = 340 * 273 / 713
<h2>
P₂ = 130.18 kPa</h2>
Hope this helps
Answer:
There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C
Explanation:
<u>Step 1: </u>Data given
mass of water = 300 grams
initial temperature = 10°C
final temperature = 50°C
Temperature rise = 50 °C - 10 °C = 40 °C
Specific heat capacity of water = 4.184 J/g °C
<u>Step 2:</u> Calculate the heat
Q = m*c*ΔT
Q = 300 grams * 4.184 J/g °C * (50°C - 10 °C)
Q = 50208 Joule = 50.2 kJ
There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C
