Colby's experiment follows model B.
Jaquan's experiment follows model B as well.
Because they are doubling, you will raise 2 to the power that represents how many times in a 24 hour period It will double.
24÷2 = 12.
24÷3 = 8.
Answer:
15
Step-by-step explanation:
Let n(T) denotes total surveys done i.e. n(T)=140
Let n(A) be the no. of responses to positively to effectiveness i.e. n(A)=71
Let n(B) be the no. of side effects i.e.n(B) =60
Let n(C) be the no. of responses to cost i.e. n(C)= 65
33 responded positively to both effectiveness and side effects
So, n(A∩B)=33
31 to effectiveness and cost
n(A∩C)=31
28 to side effects and cost
n(B∩C)=28
21 to none of the items
So, n(A∪B∪C)=140-21 = 119
we are supposed to find ow many responded positively to all three i.e. n(A∩B∩C)
Formula:
n(A∪B∪C)=n(A)+n(B)+n(C)-n(A∩B)-n(A∩C)-n(B∩C)+ n(A∪B∪C)
119=71+60+65-33-31-28+ n(A∪B∪C)
119=104+ n(A∪B∪C)
119-104= n(A∪B∪C)
15= n(A∪B∪C)
Hence 15 responded positively to all three
<span>no está en mi equipo lo siento</span>
The answer for 10x - 2y = 20 is y= 5x - 10
The answer for 5x = y + 10 is y = 5x - 10
so basically from this 5x - 10 is the results and 10x - 2y = 20 and 5x = y + 10 are different problems that lead to the same result, hope this helps
Given data:
The first set of equations are x+y=4, and x=6.
The second set of equations are 3x-y=12 and y=-6.
The point of intersection of first set of te equations is,
6+y=4
y=-2
The first point is (6, -2).
The point of intersection of second set of te equations is,
3x-(-6)=12
3x+6=12
3x=6
x=2
The second point is (2, -6).
The equation of the line passing through (6, -2) and (2, -6) is,
Thus, the required equation of the line is y=x-8.
