2.48 rounded to the nearest hundredth pl

Mathematics

1 answer:

olga_2 [115]2 years ago

8 0

Answer:

2.50

Step-by-step explanation:

2.50 might be the answer

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Considering the expression x/2 + y2. Which statements are true?Mark all that apply.

Svet_ta [14]

Answer:

D. 8/2 +(-10)² = 104

Step-by-step explanation:

To find which statements are true, evaluate the expression for the given variable values. You do this by putting the numbers in place of the respective variables, then doing the arithmetic.

The respective expression values are ...

A 83 ≠ 37 . . . . (4/2) +9² = 2 +81 = 83

B 31 ≠ 61

C 52 ≠ 61

D 104 =104 . . . . true statement

I find it less tedious to write a function into a calculator or spreadsheet and let it do the repetitive math. Examples of the calculation are shown above.

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Crm%20%5Cint_%7B0%7D%5E%7B%20%20%5Cpi%20%7D%20%5Ccos%28%20%5Ccot%28x%29%20%20%20%20-%20%2

Nikolay [14]

Replace x with π/2 - x to get the equivalent integral

$\displaystyle \int_{-\frac\pi2}^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

but the integrand is even, so this is really just

$\displaystyle 2 \int_0^{\frac\pi2} \cos(\cot(x) - \tan(x)) \, dx$

Substitute x = 1/2 arccot(u/2), which transforms the integral to

$\displaystyle 2 \int_{-\infty}^\infty \frac{\cos(u)}{u^2+4} \, du$

There are lots of ways to compute this. What I did was to consider the complex contour integral

$\displaystyle \int_\gamma \frac{e^{iz}}{z^2+4} \, dz$

where γ is a semicircle in the complex plane with its diameter joining (-R, 0) and (R, 0) on the real axis. A bound for the integral over the arc of the circle is estimated to be

$\displaystyle \left|\int_{z=Re^{i0}}^{z=Re^{i\pi}} f(z) \, dz\right| \le \frac{\pi R}{|R^2-4|}$