Answer:
pi × 18cm^2
Or approximately,
56.52cm^2 (using 3.14 for pi)
or
56.5487cm^2 (using pi button on calculator)
Step-by-step explanation:
Area of a circle is pi times [radius squared].
All circles are 360°.
Problem can be solved by finding area of whole circle, and then using ratios.
Whole Circle: area = pi × (9cm)^2 = pi × 81cm^2
80° / 360° = Area[shaded] / (pi × 81cm^2)
pi × 18cm^2 = Area[shaded]
((If you read my answer before the edit, I am sorry. I made a calculator error.))
Answer:
x = 10
Step-by-step explanation:
Solve for x:
2 (x + 2) - 7 + x = 27
2 (x + 2) = 2 x + 4:
2 x + 4 + x - 7 = 27
Grouping like terms, 2 x + x - 7 + 4 = (2 x + x) + (4 - 7):
(2 x + x) + (4 - 7) = 27
2 x + x = 3 x:
3 x + (4 - 7) = 27
4 - 7 = -3:
3 x + -3 = 27
Add 3 to both sides:
3 x + (3 - 3) = 3 + 27
3 - 3 = 0:
3 x = 27 + 3
27 + 3 = 30:
3 x = 30
Divide both sides of 3 x = 30 by 3:
(3 x)/3 = 30/3
3/3 = 1:
x = 30/3
The gcd of 30 and 3 is 3, so 30/3 = (3×10)/(3×1) = 3/3×10 = 10:
Answer: x = 10
I think 10. Is 1/20
3/4=15/20
4/5=16/20
So Allison hiked 1/20 more than Patrick
<h2>
Answer with explanation:</h2>
Let 
be the average starting salary ( in dollars).
As per given , we have
Since 
is left-tailed , so our test is a left-tailed test.
WE assume that the starting salary follows normal distribution .
Since population standard deviation is unknown and sample size is small so we use t-test.
Test statistic : 
, where n= sample size , 
= sample mean , s = sample standard deviation.
Here , n= 15 , 
, s= 225
Then, 
Degree of freedom = n-1=14
The critical t-value for significance level α = 0.01 and degree of freedom 14 is 2.62.
Decision : Since the absolute calculated t-value (2.07) is less than the critical t-value., so we cannot reject the null hypothesis.
Conclusion : We do not have sufficient evidence at 1 % level of significance to support the claim that the average starting salary of the graduates is significantly less that $42,000.
