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Oduvanchick [21]

2 years ago

6

Write the quadratic equation in standard form: 7x + 8 + 2x2 2x + 1 + x2

1 answer:

JulsSmile [24]2 years ago

5 0

Answer:

$3x^2 + 9x +9$

Step-by-step explanation:

Given

$(7x + 8 + 2x^2) + (2x + 1 + x^2)$

Required

The result in standard form

We have:

$(7x + 8 + 2x^2) + (2x + 1 + x^2)$

Remove brackets

$7x + 8 + 2x^2 + 2x + 1 + x^2$

Collect like terms

$7x+ 2x + 8 + 1 + 2x^2+ x^2$

$9x + 9+ 3x^2$

The standard form of a quadratic equation is:

$ax^2 + bx + c$

So, we have:

$9x + 9+ 3x^2$

$3x^2 + 9x +9$

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3 years ago

Given the acceleration, initial velocity, and initial position of a body moving along a coordinate line at time t, find the body

nika2105 [10]

Answer:

The position at time t is $s(t) = 8t^2 - 14t -8$

Step-by-step explanation:

From the question we are told that

The acceleration is $a = 16$

The velocity at t = 0 is $v(0) = -14$

The position at time t = 0 is $s(0) = -8$

Generally acceleration is mathematically represented as

$a(t) = \frac{d v}{dt }$

=> $\frac{dv}{dt} = 16$

=> $dv = 16 dt$

integrating both sides we have

$\int\limits dv = \int\limits16 dt$

=> $v(t) = 16 t + c$

Now at t = 0

$v(0) = 16 * 0 +c = -14$

=> $c = -14$

So

$v(t) = 16 t -14$

Generally the position of the body is mathematically represented as

$s(t) = \int\limits v(t)dt$

So

$s(t) = \int\limits 16t - 14 dt$

So

$s(t) = 16 \frac{t^2}{2} - 14t + C$

Now at t = 0

$s(0) = 16 \frac{0^2}{2} - 14(0) + C = -8$

=> $C = -8$

So

$s(t) = 8t^2 - 14t -8$

5 0

3 years ago

(picture) Factoring Polynomials: GCF PLEASEE HELP!!!!!<br> a<br> b<br> c<br> d

kramer

For this case we must find the greatest common factor of both expressions, the GFC will be the greatest number that is a factor of both numbers, that is:

The number 4 is the greatest number that divides 32 and 12 resulting in a whole number.

$\frac {32} {4} = 8\\\frac {12} {4} = 3$

In addition, both expressions have as a common factor, $a ^ 2$ :

$4a ^ 2 (8a + 3)$

Thus, $32a ^ 3 + 12a ^ 2 = 4a ^ 2 (8a + 3)$

Answer:

$4a ^ 2 (8a + 3)$

Option A

3 0

3 years ago