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Arisa [49]
3 years ago
6

SOMEONE PLEASE HELP ME I BEG IF YOU I WILL EVEN NAME MY CHILDREN AFTER YOUUU

Mathematics
1 answer:
ankoles [38]3 years ago
3 0
3 is the max number of games she could buy
75-28 leaves 47 left divide by 15 per game
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Please help I will give brainliest only to those who answer respectfully and the best answer
lukranit [14]

Step-by-step explanation:

I would say teach them easy stuff like 5+5 and number problems such as Sarah has 10 apples and takes away five apples,How many apples does Sarah have now?

4 0
2 years ago
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Is the answer English?
Vesnalui [34]
Yes indeed it is. Your correct
3 0
3 years ago
Solve the system of equations 10×+7y=99andy-×=2?
djverab [1.8K]
You can use substitution and solve y-x=2 for y which is y= x+ 2 and plug it into the y of the other equasion and you get x=5 y=7
8 0
3 years ago
Hi- I need help please to get my HS diploma...did not graduate :(
andrew-mc [135]

The remainder from the division of the algebraic equation is -53/8.

<h3>What is the remainder of the algebraic expression?</h3>

The remainder of the algebraic expression can be determined by using the long division method.

Given that:
\mathbf{f(x) = \dfrac{x^3 - 6x^2 + 3x - 1}{2x-3}}

where:

  • The divisor = 2x -3

Using the long division method, we have:

\mathbf{= \dfrac{x^2}{2} +\dfrac{-\dfrac{9x^2}{2}+3x -1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} +\dfrac{-\dfrac{-15x}{4}-1 }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}+\dfrac{-\dfrac{53}{8} }{2x-3}}

\mathbf{= \dfrac{x^2}{2}-\dfrac{9x}{4} -\dfrac{15}{8}-\dfrac{53 }{8(2x-3)}}

Therefore, we can conclude that the remainder is -53/8.

Learn more about the division of algebraic equations here:

brainly.com/question/4541471

#SPJ1

8 0
2 years ago
If two opposite sides of a quadrilateral are perpendicular and congruent, then the quadrilateral is a parallelogram.
romanna [79]
B. False.  hope I could help:)
6 0
3 years ago
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