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Mashcka [7]
3 years ago
8

CAN SOMEONE PLEASE HELP ME???

Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

D if im wrong im sorry

Step-by-step explanation:

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Angles 5 and 2 are??
Fed [463]

Answer:

Angles 5 and angle 2 are supplementary angles

Step-by-step explanation:

Angle 2 and angle 6 are corresponding angles and corresponding angles are equal when we have parallel lines

Angles 5 and angle 6 are supplementary angles since they form a line

Replace angle 6 with angle 2 since they are equal

Angles 5 and angle 2 are supplementary angles

5 0
3 years ago
If BD bisects ABC, m DBC =79 and ABC = (9x-4) find the value of x
zimovet [89]

Answer:

x=18

Step-by-step explanation:

set up the equation:

DBC+DBC=ABC

79+79=(9x-4)

Simplify both sides of the equation.

79+79=9x−4

79+79=9x+−4

(79+79)=9x−4(Combine Like Terms)

158=9x−4

158=9x−4

Flip the equation.

9x−4=158

Add 4 to both sides.

9x−4+4=158+4

9x=162

Divide both sides by 9.

9x /9  =  162 /9

x=18

3 0
3 years ago
Divide three fourths ÷ two fifths
KengaRu [80]
Your answer would be on eof the three
15/8
1.875
1 7/8
Hope this helps...
7 0
2 years ago
Read 2 more answers
Evaluate the function f(x) at the given numbers (correct to six decimal places). F(x) = x2 − 5x x2 − x − 20 , x = 5.5, 5.1, 5.05
exis [7]

we are given

f(x)=\frac{x^2-5x}{x^2-x-20}

Firstly, we will simplify it

f(x)=\frac{x(x-5)}{(x-5)(x+4)}

f(x)=\frac{x}{(x+4)}

At x=5.5:

we can plug x=5.5

f(5.5)=\frac{5.5}{(5.5+4)}

f(5.5)=0.578947

At x=5.1:

we can plug x=5.1

f(5.1)=\frac{5.1}{(5.1+4)}

f(5.1)=0.56043956

At x=5.05:

we can plug x=5.05

f(5.05)=\frac{5.05}{(5.05+4)}

f(5.05)=0.558011

At x=5.01:

we can plug x=5.01

f(5.01)=\frac{5.01}{(5.01+4)}

f(5.01)=0.5560488

At x=5.005:

we can plug x=5.005

f(5.005)=\frac{5.005}{(5.005+4)}

f(5.005)=0.5558023

At x=5.001:

we can plug x=5.001

f(5.001)=\frac{5.001}{(5.001+4)}

f(5.001)=0.5556049

At x=4.9:

we can plug x=4.9

f(4.9)=\frac{4.9}{(4.9+4)}

f(4.9)=0.5505617

At x=4.95:

we can plug x=4.95

f(4.95)=\frac{4.95}{(4.95+4)}

f(4.95)=0.5530726

At x=4.99:

we can plug x=4.99

f(4.99)=\frac{4.99}{(4.99+4)}

f(4.99)=0.55506117

At x=4.995:

we can plug x=4.995

f(4.995)=\frac{4.995}{(4.995+4)}

f(4.995)=0.55503085

At x=4.999:

we can plug x=4.999

f(4.999)=\frac{4.999}{(4.999+4)}

f(4.999)=0.55550616



7 0
3 years ago
Simplify the following expression 5-⁵/2 x 5⁹/2
yarga [219]

Given:

Consider the given expression is

5^{-\frac{5}{2}}\times 5^{\frac{9}{2}}

To find:

The simplified form of the given expression.

Solution:

We have,

5^{-\frac{5}{2}}\times 5^{\frac{9}{2}}

Using properties of exponents, we get

=5^{-\frac{5}{2}+\frac{9}{2}}           [\because a^ma^n=a^{m+n}]

=5^{\frac{-5+9}{2}}

=5^{\frac{4}{2}}

=5^{2}

=25

Therefore, the simplified form of given expression is 25.

7 0
3 years ago
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