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Social Studies

1 answer:

wel2 years ago

8 0

Answer:

umbo gumbo RUMBO get the duck out of here

Explanation:

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Embryonic stem cells derived from blastocysts are pluripotent, and therefore useful in stem cell research because they ________.

Elanso [62]

Answer:

The answer is: They not only serve for Regenerative Medicine, but also for the "screening" of new drugs, and some other things.

Explanation:

Currently, studies in regenerative medicine are aimed at research and knowledge of induced pluripotent cells (iPSCs). For some, they are the cells called to take over from embryonic stem cells (ESCs), which until recently were the main objective of research in this field of biomedicine.

Since the first cultures of mouse embryonic cells derived from blastocysts were obtained in 1981, the foundations were laid for the development of the necessary methodologies that would lead later to generate human embryonic cells with characteristics similar to those of the mouse.

In addition to their interest in Regenerative Medicine, these types of cells are a tool of great value for the "screening" of new drugs, as well as a model to study the etiology of diseases that originate during the embryonic stage, and to study processes that occur during human embryonic development .

The answer is: They not only serve for Regenerative Medicine, but also for the "screening" of new drugs, and some other things.

8 0

3 years ago

A basketball is dropped from the edge of a cliff at the same time that second basketball is thrown upward from the ground. When

pentagon [3]

Answer:

The collision occurs at a height of 1/3 of the total height of cliff.

Explanation:

The situation is represented in the attached figure:

For the stone dropped from top of cliff we have

Initial velocity of drop= 0 m/s.

Now the time at which it attains a velocity of 2v is obtained from first equation of kinematics as

$v_{f}=u_{i}+gt\\\\2v=0+gt\\\\\therefore t=\frac{2v}{g}$

Thus the distance it covers in this time can be calculated using third equation of kinematics as

$v_{f}^{2}=v_{i}^{2}+2gh\\\\(2v)^{2}=2gh_{1}\\\\\therefore h_{1}=\frac{2v^{2}}{g}$

For the stone thrown upwards the velocity at collision is give as 'v' thus the velocity at which it is thrown upwards can be calculated by first equation of kinematics as

$v=v_{i}-gt\\\\\therefore v_{i}=v+gt\\\\v_{i}=v+g\times \frac{2v}{g}\\\\\therefore v_{i}=3v$