Answer:
1. loans
2. credit
3. interest
4. total value
5.
6.
7. compound
8. principal
9.
10.
Step-by-step explanation:
I don't know what 5, 6, 9, or 10 is
Answer:
Part a) The elevation of the road is ![6\°](https://tex.z-dn.net/?f=6%5C%C2%B0)
Part b) The rise is ![0.2\ km](https://tex.z-dn.net/?f=0.2%5C%20km)
Step-by-step explanation:
Part a) What is the elevation of the road to the nearest degree?
Let
y-----> the rise of the road ( vertical distance)
x ----> the run of the road (horizontal distance)
we have
y/x=1/10
we know that
The ratio y/x is equal to the tangent of the angle of the elevation of the road
Let
----> angle of the elevation of the road
![tan(\theta)=y/x](https://tex.z-dn.net/?f=tan%28%5Ctheta%29%3Dy%2Fx)
![tan(\theta)=1/10](https://tex.z-dn.net/?f=tan%28%5Ctheta%29%3D1%2F10)
![\theta=arctan(1/10)=6\°](https://tex.z-dn.net/?f=%5Ctheta%3Darctan%281%2F10%29%3D6%5C%C2%B0)
Part b) If the road is two km long, how much does it rise?
using proportion
![1/10=y/2](https://tex.z-dn.net/?f=1%2F10%3Dy%2F2)
![y=2/10=0.2\ km](https://tex.z-dn.net/?f=y%3D2%2F10%3D0.2%5C%20km)
So for example B(4,1) so x=4, y=1
->B'(4-2,1-4)
->B'(2,-3)
->A'(1-2,1-4)
->A'(-1,-3)
->C'(4-1,-2-4)
->C'(3,-6)
->D'(1-2,-2-4)
->D'(-1,-6)
so the image of the rectangle ABCD->A'B'C'D'
Answer:
100
cm² or 314.16 cm²
Step-by-step explanation:
First, you should find the radius of the circle, which is half the diameter.
r = 10 cm
The area of the circle =
r²
So you just need to plug in and multiply everything.
A =
10²
= 100
cm²
Usually, you can leave it in terms of pi, but otherwise
= 314.16 cm²
Ok, esto seria algo así. Primero, ya que 3/8 esta cerca de 4/8 ó 1/2, este seria 1/2. y ya que 1/12 esta mas cerca a 0 que 1/2, este seria 0. 1/2 + 0 = 1/2. El estimado para esto seria 1/2.