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2 years ago

(a

ign="absmiddle" class="latex-formula">

Mathematics

1 answer:

andre [41]2 years ago

7 0

Answer:

$3a {x}^{4}$

Step-by-step explanation:

remeber that idical laws

${x}^{a} \times {x}^{b} = {x}^{a + b}$

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Will give brainliest

Katen [24]

Answer:

Trapezoid

Step-by-step explanation:

The two sloped opposite sides are congruent. The two uncongruent opposite sides are parallel. There are no right angles. You can do this by finding the distance and slopes of the lines.

Not triangle because has four vertices.

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2 years ago

Stephanie saw an ad in the paper that her favorite kind of perfume was on sale for 25% off. Her favorite perfume costs $20 per b

Natalija [7]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B25%20%7D%7B5%20%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B5%7D%20" id="TexFormula1" title

Sliva [168]

Answer:
25/5+1/5
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2 years ago

If this number is larger than 6, then its square is larger than 36.The number is not larger than 6.therefore Its square is not l

Anit [1.1K]

Answer:

False

Step-by-step explanation:

If this number is larger than 6, then its square is larger than 36.

If x > 6, then x² > 36

The number is not larger than 6.therefore Its square is not larger than 36.

x ≤ 6; therefore, x² ≤ 36

-7 is < 6; however -7² > 36 as -7² = 49

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2 years ago

Write a possible third degree polynomial with integer coefficient that have zeros: 1 2i, -4. Assume the leading coefficient to b

jasenka [17]

Answer:

The polynomial is:

$p(x) = x^3 + 2x^2 - 3x + 20$

Step-by-step explanation:

A third degree polynomial can be written in function of it's zeros $x_1, x_2, x_3$ the following way:

$p(x) = a(x - x_1)(x - x_2)(x - x_3)$

In which a is the leading coefficient.

Integer coefficient that have zeros: 1+2i, 1-2i, -4

Leading coefficient: 1

$p(x) = 1(x - (1+2i))(x - (1-2i))(x - (-4))$

$p(x) = (x - 1 -2i)(x - 1 + 2i)(x + 4)$

$p(x) = ((x-1)^2 - (2i)^2)(x + 4)$

$p(x) = (x^2 - 2x + 1 - 4i^2)(x + 4)$

Since $i^2 = -1$

$p(x) = (x^2 - 2x + 1 + 4)(x + 4)$

$p(x) = (x^2 - 2x + 5)(x + 4)$

$p(x) = x^3 + 4x^2 - 2x^2 - 8x + 5x + 20$

$p(x) = x^3 + 2x^2 - 3x + 20$

3 0

2 years ago