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Svetradugi [14.3K]
3 years ago
10

Express in exponential form. log 3 a = n

Mathematics
1 answer:
agasfer [191]3 years ago
4 0

Answer:

\log_3(a)=n has exponential form 3^n=a.

\log(3a)=n has exponential form 10^{n}=3a.

Please let me know if neither of my interpretations of your problem/question is correct.  That is I can either assume you wrote \log_3(a)=n  or \log(3a)=n.

If something else was intended, please let me know. Thanks kindly.

Step-by-step explanation:

Let's assume: \log_3(a)=n.

The base is 3.

The exponent is n. (Just remember the logarithm is the exponent.)

So we have 3^n=a

In general these forms are equivalent:

log_b(a)=y \text{ is equivalent to } b^y=a.

\log(3a)=n is the same as \log_{10}(3a)=n

The base is 10 (if you don't see a base and log is written).

The exponent is n.

So we have 10^n=3a.

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Given:

Subtract the sum of (5^3 + 7^2-9) and (7 + 3^2) from the sum of (5^3 + 6) and (10^2-12).

To find:

The simplified value for the given statement.

Solution:

The sum of (5^3 + 7^2-9) and (7 + 3^2)

Sum_1=5^3+7^2-9+7 + 3^2

Sum_1=125+49-9+7 + 9

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Sum_2=5^3 + 6+10^2-12

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