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malfutka [58]
3 years ago
12

Please help. i need this done today

Mathematics
1 answer:
Naily [24]3 years ago
7 0

Answer:

herlojffhgdxvjdxhyeb olis the tim view on the euros 2020 final

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The daily number of minutes a drummer practiced drumming during a week are 48, 42, 48, 46, 49, 52, 45, and 50.
Sedaia [141]

Answer:

b

Step-by-step explanation:

8 0
3 years ago
Simplify the following expression:<br><br> -3(x+6)+8x<br> 3x-25<br> 5x-22<br> -11+3x<br> 5x-18
Alina [70]

Answer:

5x -18

<h2>I hope this helped! </h2><h3>have a nice day! :)</h3>
3 0
3 years ago
Read 2 more answers
Limit xtens to 0 x^2logx^2 what is the ans of interminate forms?
GarryVolchara [31]

Rewrite the limit as

\displaystyle\lim_{x\to0}x^2\log x^2=\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}

Then both numerator and denominator approach infinity (with different signs, but that's not important). Applying L'Hopital's rule, we get

\displaystyle\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}=\lim_{x\to0}\frac{\frac2x}{-\frac2{x^3}}=\lim_{x\to0}-x^2=\boxed{0}

7 0
3 years ago
A rectangle has a perimeter of 72 feet. The length is twice the width. Find the dimensions of the rectangle......
denpristay [2]
Set up a system of equations:
2l + 2w = 72
l = 2w

Solve the system using substitution:
2(2w) + 2w = 72
Solve for w:
4w + 2w = 72
—> 6w = 72
—> w = 12

Plug in the value for ‘w’ in the second equation:
l = 2(12)
—> l = 24

The width is 12.
The length is 24.
4 0
3 years ago
Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial t
jekas [21]

Answer:

(12.1409, 14.0591

Step-by-step explanation:

Given that Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial transport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known.

Group   Group One     Group Two  

Mean 87.600 74.500

SD 1.000 1.500

SEM 0.316 0.433

N 10      12    

The mean of Group One minus Group Two equals 13.100

standard error of difference = 0.556

 90% confidence interval of this difference:  

(13.1-1.725*0.556,13.1+1.725*0.556)\\=(12.1409, 14.0591)

  t = 23.5520

 df = 20

4 0
3 years ago
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