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pantera1 [17]
3 years ago
7

Please help me thank ​

Mathematics
1 answer:
Dafna11 [192]3 years ago
6 0

Answer:

laccolith

Step-by-step explanation:

A laccolith is a dome shaped intrusive body that has intruded between layers of sedimentary rock. The rising magma forces the overlying layers to rise up into a dome

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Find the area of the shape shown below.
maw [93]

Answer:

The area is 28.

Step-by-step explanation:

Visualize the rectangle as 2 split squares.

The top square is easily 4x4, so the area of that part is 16.

Now visualize the bottom square as two rectangles.

To find the area of the dented side, you would use the equation of finding the area of a triangle, a=(w x h)\frac{1}{2} because the dented side is actually just one half of the rectangle on the other side.

Since it is the same height as the top square, but is 2 in width, it would be written as a=(2 x 4)\frac{1}{2} . So the area of that part is 4, and the area of the other rectangle would be just 2 x 4 so it is 8.

Totaling these numbers, you get the area of the full rectangle.

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Solve for c. 9c +4= -5c + 14+ 13c
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What is the difference between a Linear Graph and an Exponential Graph?
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Linear functions change at a constant rate per unit interval. An exponential function changes by a common ratio over equal intervals.

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An isosceles triangle’s altitude will bisect its base. Which expression could be used to find the area of the isosceles triangle
omeli [17]

Answer:

\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}

Step-by-step explanation:

The length of the base is the distance between the points 4+2i and 10+4i, so

\text{Base}=|10+4i-(4+2i)|=|10+4i-4-2i|=|6+2i|=\sqrt{6^2+2^2}=\\ \\=\sqrt{36+4}=\sqrt{40}

The middle point of the base is placed at point

\dfrac{4+2i+10+4i}{2}=\dfrac{6i+14}{2}=7+3i

The length of the height is the distance between the points 5+9i and 7+3i

\text{Height}=|5+9i-(7+3i)|=|5+9i-7-3i|=|-2+6i|=\sqrt{(-2)^2+6^2}=\\ \\=\sqrt{4+36}=\sqrt{40}

So, the area of the triangle is

A=\dfrac{1}{2}\cdot \text{Base}\cdot \text{Height}=\dfrac{\sqrt{40}\cdot \sqrt{40}}{2}

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