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3 years ago

Need help on this one

Mathematics

2 answers:

11Alexandr11 [23.1K]3 years ago

5 0

Answer:

slope is -1/7 and y intercept is 2

Step-by-step explanation:

Misha Larkins [42]3 years ago

5 0

Slope is -1/7 and y-int is 2
slope will always be the number in front of x for the y=mx+b formula

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Please answer this math question

IgorC [24]

0.
1/2 = 1/2
No need to add anything

8 0

3 years ago

The class sizes of elementary school classes in a public school district are normally distributed with an unknown population mea

weqwewe [10]

Answer: $(17.14,\ 22.86)$

Step-by-step explanation:

The confidence interval estimate for the population mean is given by :-

$\overline{x}\pm ME$ , where $\overline{x}$ is the sample mean and ME is the margin of error.

Given : Sample mean: $\overline{x}=20$

The margin of error for a 98% confidence interval estimate for the population mean using the Student's t-distribution : $ME=2.86$

Now, the confidence interval estimate for the population mean will be :-

$20\pm2.86=(20-2.86,\ 20+2.86)=(17.14,\ 22.86)$

Hence, the 98% confidence interval estimate for the population mean using the Student's t-distribution = $(17.14,\ 22.86)$

8 0

3 years ago

A pet supplier has a stock of parakeets of which 20% are blue parakeets. A pet store orders 3 parakeets from this supplier. If t

Levart [38]

Answer:

0.384

Step-by-step explanation:

pet supplier has a stock of parakeets of which 20% are blue parakeets

20/100 = 0.2 blue parakeets (success)

1-0.2 = 0.8 not parakeets (not success)

A pet store orders 3 parakeets from this supplier

we need to find the chance of getting exactly one blue from 3 parakeets

$P(x=1)=nCr (p)^r(q)^{n-r}$

n=3, r=1, p = 0.2 , q=0.8

$P(x=1)=3C1 (0.2)^1(0.8)^{2}$

0.384

5 0

3 years ago

One person wants to get a 95% z-confidence interval with a margin of error of at most 15 based on a population standard deviatio

Bess [88]

Answer:

$n=(\frac{1.96(60)}{15})^2 =61.46 \approx 62$

So the answer for this case would be n=62 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample