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lapo4ka [179]
3 years ago
5

In fact, Jilly often looked forward to the warmth of the greenhouse and feeling the heat seep into her bones.

Mathematics
1 answer:
Hoochie [10]3 years ago
6 0
C. She loves her job
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these tables of values represent continuous functions. for which function will the y-value be the greatest for very large values
Gelneren [198K]

Answer:

Option A.

Step-by-step explanation:

We need to find a table for which the y-value will be the greatest for very large values of x.

From the given table it is clear that the largest value of x in all tables is 5.

In table A, y=64 at x=5.

In table B, y=32 at x=5.

In table C, y=40 at x=5.

In table D, y=13 at x=5.

It is clear that 64 is the greatest value among 64, 32, 40 and 13.

It means table in option A represents the function for which the y-value will be the greatest for very large values of x.

Therefore, the correct option is A.

3 0
3 years ago
What is -3 1/6+5 3/5<br> help me please and thank you
balandron [24]
The answer should be 2 13/30.
6 0
3 years ago
What is a ordered pair of numbers that identify a point on a coordinate plane
Paraphin [41]

Answer:A point is named by its ordered pair of the form of (x, y). The first number corresponds to the x-coordinate and the second to the y-coordinate. To graph a point, you draw a dot at the coordinates that corresponds to the ordered pair.

I HOPE IT HELPS :D

6 0
2 years ago
please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

6 0
3 years ago
???? ??? Answer ....
devlian [24]
Answer would be C because the cost is independent
3 0
3 years ago
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