To calculate the frequency of the heterozygote genotype (Pq) for this gene we must use the Hardy-Weinberg equation ( p2 + 2pq + q2 = 1 ). This equation relies on the Hardy-Weinberg principle, a model in population genetics that states that the frequency of the alleles in a population is never changing, only the combinations (the genotypes) are changing.
If there are only two alleles (variations) of this gene in a population, then their frequencies should add up to 1 (100%). From this, we can calculate the frequency of the q allele.
p +q=1
0,3 +q=1
q= 1-0,3
q= 0,7
Now hat we have the frequency of the q allele we can use the HW equation to calculate the frequency of the heterozygotes.


0,09 + 2pq +0.49= 1
2pq +0,58= 1
2pq= 1-0.58
2pq=0,42
The freqency of the heterozygotes in this population is 0.42
<span>Two prokaryotes turning into a eukaryotic cell began with a process called
endosymbiosis. One large prokaryote engulfs (a process called
endocytosis) one small, aerobically respiring prokaryote. The small
prokaryote turned into a membrane-bound organelle, which prokaryotes do
not have, and like we know, only eukaryotes have membrane-bound
organelles. So that is how the eukaryotic cell structure evolved from
prokaryotic cells, meaning that before this evolution, they were most likely symbiotic.</span>
Answer:
A) 50%
Explanation:
Boxes 2 and 3 are heterozygous because solving the punnet square results in those boxes being Tt