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Verdich [7]
3 years ago
10

Quien mira WWE.Respondan!​

Engineering
1 answer:
Mandarinka [93]3 years ago
4 0

Answer:

*Spanish*

Hola aquí va la respuesta!

Yo veo la WWE y me encanta.

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The condition of irrotationality for a two-dimensional flow is satisfied when rotation w everywhere is (less than — equal to — m
Deffense [45]

Answer:

Zero.

Explanation:

Lets take velocity V is given as in 2 dimensional flow

  V=u i +v j

V=f(x,y)

u=f(x,y)

v=f(x,y)

Rotational ability ω given as

\omega =\dfrac{1}{2}\left (\dfrac{\partial v}{\partial x}-\dfrac{\partial u} {\partial x}\right)

If

ω=0 ,then flow will be  irrotational.

ω ≠0 ,then flow will be rotational.

So we can say that , ω will be zero every where for  irrotational  two dimensional flow .

5 0
3 years ago
Hello everyone, how can you draw this drawing?
dedylja [7]
I don’t see a drawing? Is there supposed to be a picture or something?
4 0
3 years ago
A 3 m aluminum pole is kept at a residential site for construction
Aliun [14]

Answer:

I don't know sorry

Explanation:

5 0
3 years ago
Need answers for these please ​
Step2247 [10]

Answer:

Following are given the answers one-by-one with explanation:

(a) 8 records

As records are the horizontal rows of data and we have 8 of them.

(b) 5 fields

As fields are vertical columns of data and we have 5 of them.

(c)E3000

As by sorting Makers_names in ascending order the last one would be Rany and by sorting Processor_type we have two option with Rany that are B1500 and E3000. We can see that E3000 will come at the end.

(d) Computer_type

As only two choices (Laptop and PC )  are being used under the column computer_type so it can be amended to contain Boolean data.

(e) format check

This will check that the field should contain one alphabet (capital letter) followed by 4 digits each.

i hope it will help you!

7 0
3 years ago
Air is compressed slowly in a piston-cylinder assembly from an initial state where P1 = 1.4 bar, V1= 4.25 m^3, to a final state
lord [1]

Answer:

W=-940.36 KJ

Explanation:

Given that

P_1=1\ bar,V_1=4.25 {m^3}

P_2=6.8\ bar

Process follows pv=constant

So this is the isothermal process and work in isothermal process given as

W=P_1V_1\ln \dfrac{P_1}{P_2}

Now by putting the values                (1.4 bar =140 KPa)

W=P_1V_1\ln \dfrac{P_1}{P_2}

W=140\times 4.25 \ln \dfrac{1.4}{6.8}

W=-940.36 KJ

Negative sign indicates that this is a compression process and work will given to the system.

7 0
4 years ago
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