Which of the following can not be used to store an electrical charge?

Which of the following animals can be found in the locality

erastovalidia [21]

Answer:

c frog

Explanation:

frog have chance that can lived in the locality or in public place like river,lake,farm and other place that they can be lived and hunt foods. In the picture bear, elephant and tiger are can't lived in the locality that have many population of people. little percent of changes that they can hunts foods or lived in the public/locatlity place.

7 0

2 years ago

700.0 liters of a gas are prepared at 760.0 mmHg and 100.0 °C. The gas is placed into a tank under high pressure. When the tank

ololo11 [35]

Answer:

The volume of the gas is 11.2 L.

Explanation:

Initially, we have:

V₁ = 700.0 L

P₁ = 760.0 mmHg = 1 atm

T₁ = 100.0 °C

When the gas is in the thank we have:

V₂ =?

P₂ = 20.0 atm

T₂ = 32.0 °C

Now, we can find the volume of the gas in the thank by using the Ideal Gas Law:

$PV = nRT$

$V_{2} = \frac{nRT_{2}}{P_{2}}$ (1)

Where R is the gas constant

With the initials conditions we can find the number of moles:

$n = \frac{P_{1}V_{1}}{RT_{1}}$ (2)

By entering equation (2) into (1) we have:

$V_{2} = \frac{P_{1}V_{1}}{RT_{1}}*\frac{RT_{2}}{P_{2}} = \frac{1 atm*700.0 L*32.0 ^{\circ}}{100.0 ^{\circ}*20.0 atm} = 11.2 L$

Therefore, When the gas is placed into a tank the volume of the gas is 11.2 L.

I hope it helps you!

5 0

2 years ago

A body is moving with simple harmonic motion. It's velocity is recorded as being 3.5m/s when it is at 150mm from the mid-positio

natima [27]

Answer:

1) A=282.6 mm

2) $a_{max}=60.35\ m/s^2$

3)T=0.42 sec

4)f= 2.24 Hz

Explanation:

Given that

V=3.5 m/s at x=150 mm ------------1

V=2.5 m/s at x=225 mm ------------2

Where x measured from mid position.

We know that velocity in simple harmonic given as

$V=\omega \sqrt{A^2-x^2}$

Where A is the amplitude and ω is the natural frequency of simple harmonic motion.

From equation 1 and 2

$3.5=\omega \sqrt{A^2-0.15^2}$ ------3

$2.5=\omega \sqrt{A^2-0.225^2}$ --------4

Now by dividing equation 3 by 4

$\dfrac{3.5}{2.5}=\dfrac {\sqrt{A^2-0.15^2}}{\sqrt{A^2-0.225^2}}$

$1.96=\dfrac {{A^2-0.15^2}}{{A^2-0.225^2}}$

So A=0.2826 m

A=282.6 mm

Now by putting the values of A in the equation 3

$3.5=\omega \sqrt{A^2-0.15^2}$

$3.5=\omega \sqrt{0.2826^2-0.15^2}$

ω=14.609 rad/s

Frequency

ω= 2πf

14.609= 2 x π x f

f= 2.24 Hz

Maximum acceleration

$a_{max}=\omega ^2A$

$a_{max}=14.61 ^2\times 0.2826\ m/s^2$

$a_{max}=60.35\ m/s^2$

Time period T

$T=\dfrac{2\pi}{\omega}$

$T=\dfrac{2\pi}{14.609}$

T=0.42 sec

8 0

3 years ago

Which factor is typically not a requisite feature of setting a career goal?

Vaselesa [24]

Answer:

Explanation: Analysing the goal of the family is not a requisite feature of setting a career goal. It is an individual person's ability and topic of interest so the family goal cannot be taken into consideration. Brainliest

Explanation:

5 0

2 years ago

. One of the earliest forms of space management was known as __________ .

Musya8 [376]

Answer: the smith system

Explanation: it was invented by Harold smith

Hope this helps :)

4 0

2 years ago