Answer:
52.2538 psia
Explanation:
The absolute pressure at depth of 27 inches can be calculated by:
Pressure = Local pressure + Gauge pressure
Also,
Where,
is the density of glycerin (
)
g is the gravitational acceleration = 32.1741 ft/s²
h = 27 in
Also, 1 in = 1/12 ft
So,
h = 27 / 12 ft = 2.25 ft
So,
Also,
1 ft = 12 inch
1 ft² = 144 in²
So,
Local pressure = 14.6 psia
So,
<u>Absolute pressure = 14.6 psia + 37.6538 psia=52.2538 psia</u>
Answer:
4.6398 kg/day
Explanation:
Please find attached file for complete answer solution.
Answer:The distinction between a permanent magnet and an electromagnet is essentially one in how the field is created, not the properties of the field afterwards. So electromagnets still have two poles, still attract ferromagnetic materials, and still have poles that repel other like poles and attract unlike poles.
Explanation:
Answer:
1) the final temperature is T2 = 876.76°C
2) the final volume is V2 = 24.14 cm³
Explanation:
We can model the gas behaviour as an ideal gas, then
P*V=n*R*T
since the gas is rapidly compressed and the thermal conductivity of a gas is low a we can assume that there is an insignificant heat transfer in that time, therefore for adiabatic conditions:
P*V^k = constant = C, k= adiabatic coefficient for air = 1.4
then the work will be
W = ∫ P dV = ∫ C*V^(-k) dV = C*[((V2^(-k+1)-V1^(-k+1)]/( -k +1) = (P2*V2 - P1*V1)/(1-k)= nR(T2-T1)/(1-k) = (P1*V1/T1)*(T2-T1)/(1-k)
W = (P1*V1/T1)*(T2-T1)/(1-k)
T2 = (1-k)W* T1/(P1*V1) +T1
replacing values (W=-450 J since it is the work done by the gas to the piston)
T2 = (1-1.4)*(-450J) *308K/(101325 Pa*650*10^-6 m³) + 308 K= 1149.76 K = 876.76°C
the final volume is
TV^(k-1)= constant
therefore
T2/T1= (V2/V1)^(1-k)
V2 = V1* (T2/T1)^(1/(1-k)) = 650 cm³ * (1149.76K/308K)^(1/(1-1.4)) = 24.14 cm³
