The answer will be:
Solubility of the mixture = 21.5/60 x 25 = 8.96
Hope this helps.
Answer:
1. Used in many smoke detectors for homes and businesses to measure levels of toxic lead in dried paint sample to ensure uniform thickness in rolling processes like steel and paper production and to help determine where oil wells should be drilled.
2.Used to treat cancerous tumors to measure correct patient dosages of radioactive pharmaceutical to measure and control the liquid flow in oil pipelines to tell researchers whether oil wells are plugged by sand and to ensure the right fill level for packages of food, drugs, and other
products.
3.Used in medical diagnosis
4.Used to treat thyroid disorders. (Graves’s disease).
5.Used in molecular biology and genetics research.
6.Used in nuclear medicine for lung ventilation and blood flow studies.
7.Used in dental fixtures like crowns and dentures to provide a Uranium-234 natural color and brightness.
8.Used in electric blanket thermostats and to gauge the thickness of thin plastics, thin sheet metal, rubber, textile and paper.
Use the equation for uniform acceleration:
distance = Vo*t + a * t^2 / 2
As the car is initially at rest, Vo = 0
=> distance = a * t^2 / 2.
Now solve for a and replace the data of time and distance:
a = 2 * distance / (t^2)
a = 2 * 120m / (6.32s)^2 = 240m / 39.9424 s^2 = 6.009 m/s^2
Which approximates to 6 m/s^2.
So, the answer is the option B.) 6 meters / second^2
Answer:
See explanation
Explanation:
1) a precipitate of lead chloride would be observed if the concentrations of both reagents was high enough and the temperature was low enough
2) A gelatinous white-ish precipitate would be observed at first, though i'm not sure what would happen with excess ammonia. The precipitate would likely not dissolve in excess ammonia
Answer:
The Kₐ of the weak acid is 1.033×10⁻⁴
Explanation:
The dissociation of a weak acid in aqueous solution is limited to about 5 to 10%
The acid dissociation reaction is given as follows;
HA (aq) + H₂O (l) → H₃O⁺(aq) + A⁻ (aq)
Given that the pH = 2.5, we have
pH = -log₁₀[H₃O⁺] = 2.5
∴ [H₃O⁺] = 10^(-2.5) = 0.0031623
Kₐ = [H₃O⁺][A⁻]/[HA] = (0.0031623^2)/(0.1 - 0.0031623) = 1.033×10⁻⁴
The acid dissociation constant, Kₐ for weak acid is very low as obtained