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insens350 [35]
3 years ago
5

[Help Please!] Find the value of x.

Mathematics
2 answers:
Tresset [83]3 years ago
8 0

Answer:

x = 52 degrees

Step-by-step explanation:

Let's first focus on the angle x + 72.  Immediately adjacent to x + 72 is angle RQS.  These two angles are "straight" in that they lie immediately adjacent to one another and add up to 180 degrees.  Then angle RQS can be expressed as

180 degrees - (x + 72 degrees), or 108 - x degrees.

The three interior angles of the triangle must add up to 180 degrees.  Hence

108 - x degrees + 34 degrees + 90 degrees = 180 degrees, and so:

108 - x + 34 = 90

This yields x = 52 degrees.

Norma-Jean [14]3 years ago
4 0

Answer:

x = 52

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles of a triangle

x+72 = 34+90

x +72 =124

Subtract 72 from each side

x = 124-72

x =52

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If a scalene triangle has its measures 4 m, 11 m and 8 m, find the largest angle.
soldier1979 [14.2K]

Answer:

129.8 approximately

Step-by-step explanation:

So this sounds like a problem for the Law of Cosines. The largest angle is always opposite the largest side in a triangle.

So 11 is the largest side so the angle opposite to it is what we are trying to find. Let's call that angle, X.

My math is case sensitive.

X is the angle opposite to the side x.

Law of cosines formula is:

x^2=a^2+b^2-2ab \cos(X)

So we are looking for X.

We know x=11, a=4, and b=8 (it didn't matter if you called b=4 and a=8).

11^2=4^2+8^2-2(4)(8)\cos(X)

121=16+64-64\cos(X)

121=80-64\cos(X)

Subtract 80 on both sides:

121-80=-64\cos(X)

41=-64\cos(X)

Divide both sides by -64:

\frac{41}{-64}=\cos(X)

Now do the inverse of cosine of both sides or just arccos( )

[these are same thing]

\arccos(\frac{-41}{64})=X

Time for the calculator:

X=129.8 approximately

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4 years ago
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