Ask question

Ask question

All categories

3 years ago

6

If it takes three men 56 minutes to fill a trench 4x6x5 and two of the men work twice as rapidly as the third, how many minutes

will it take the two faster men alone to fill this trench?

1 answer:

Oksanka [162]3 years ago

5 0

Answer:

i have no idea

Step-by-step explanation:

You might be interested in

Evaluate 2LW + 2HL + 2HW for L = 3,W = 2, and H = 4. 48 46

JulijaS [17]

2(3)(2) + 2(4)(3) + 2(4)(2)

2(6) + 2(12) + 2(8)

12 + 24 + 16

52

Hope this helps!

7 0

3 years ago

Read 2 more answers

Please help: (picture)

Slav-nsk [51]

We need to solve the speed formula for d. To do so, let's start by moving the number of the left hand side:

$\frac{S}{356} = \sqrt{d}$

Square both sides to get rid of the square root:

$\frac{S^2}{126736} = d$

Now plug the known value of the speed to find the distance:

$d = \frac{140^2}{126736} = \frac{19600}{126736} \approx 0.15465$

So the closest answer is the last one: d=0.155km

3 0

3 years ago

Abby has x dolls. Lauren has 9 times as many as Abby. Betsy has 7 fewer than Lauren. How many dolls do they have in all?

makkiz [27]

Answer: x + 9x + (9x - 7)

Simplified: 19x - 7

Step-by-step explanation: We see that Abby already starts off with x dolls. We put a 9 infront of the x for the second part of the expression because Lauren has 9 times as many dolls as Abby. Since Betsy has 7 less than Lauren, we take away 7 from 9x. We put that part in parenthesis because that part needs to be done first before we add everything together. Once simplified, we have "19x - 7". (I really tried my best so I hope this is the correct answer!)

5 0

3 years ago

Read 2 more answers

Rewrite using a single positive exponent.<br> 6^5<br> 6

Fiesta28 [93]

Answer:

$6^{4}$

Step-by-step explanation:

using the rule of exponents

$\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$

note that 6 = $6^{1}$ , then

$\frac{6^{5} }{6}$ = $6^{(5-1)}$ = $6^{4}$

7 0

3 years ago

The weekly sales of Honolulu Red Oranges is given by q = 990 − 22p. Calculate the price elasticity of demand when the price is $

elena55 [62]

Answer:

E = -2. The demand is going down by 2% per 1% increase in price at that price level.

The price that gives a maximum revenue is $22.5. The maximum revenue is $9112.5

Step-by-step explanation:

The overall demand formula: Q = aP + b

Q = 990 - 22P

<u>Demand elasticity:</u>

At P = $30, the Q = 990 - 22×30 = 330. a = $\frac{dQ}{dP}$ = -22

The formula for demand elasticity: E = $\frac{dQ}{dP}$ × $\frac{P}{Q}$

Demand elasticity at $30: E = -22 × $\frac{30}{330}$ = -2

So, The demand will be going down by 2% if 1% increase in price.

<u>Revenue:</u>

R = P×Q = P×(990 - 22P) = -22P² - 990P

R' = -44P - 990. The revenue is maximum when R' = 0

⇔0 = -44P - 990 ⇔ P = $22.5

At the P = $22.5, the Q = 990 - 22×22.5 = 495.

The maximum revenue = $22.5×495 = $11,137.5

7 0

3 years ago