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Bess [88]
3 years ago
10

For the linear model, y = -67.9x + 679 , the distance, in miles y, is a function of time, x, in hours. Use the model to calculat

e the total distance, in miles, at x = 5 hours.
Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0

Answer:

339.5

Step-by-step explanation:

-67.9x+679= y

-67.9*5+679=

-339.5+679= 339.5

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HELP FAST LOL HAHAHAH
OleMash [197]

Answer:

184

Step-by-step explanation:

First, note that the sides that are opposite to each other are congruent (this will come into play in a second). We can find the area of each triangle by doing 0.5(b)(h) (aka half * base* height). Since we've established tha opposite sides are congruent and the triangles are opposite to each other, they must be congruent. That means that the area is going to be the exact same for both triangles. So, we get the expression (0.5)(6)(4)(2), which comes out to 6*4 = 24. Then, to find the area of the 2 rectangles that are the sides, just do 5*10*2 = 100 square meters for both rectangles combines. Lastly, we need to find the area of the floor. The dimensions of the floor are 6 and 10, so we just do 6*10 = 60. Now, add all those numbers together. We get 100+60+24 = 184. Hope this helps! Let me know if anything is still confusing.

4 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
barxatty [35]

Step-by-step explanation:

I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.

y = -16x² + 64x + 89

shows us that the tower is 89 ft tall (the result for x = 0, at the start).

anyway, if the original assumption is correct, then we need to solve

0 = -16x² + 64x + 89

the general solution for such a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/)2a)

in our case

a = -16

b = 64

c = 89

x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =

= (-64 ± sqrt(4096 + 5696))/-32 =

= (-64 ± sqrt(9792))/-32

x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s

x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s

the negative solution for time is but useful here (it would be the time calculated back to ground at the start).

so, x2 is our solution.

the rocket hits the ground after about 5.09 seconds.

5 0
2 years ago
The scale of this map is 1 inch = 50 miles. The ruler measures the distance between Gary, Indiana, and Traverse City, Michigan,
levacccp [35]

Answer:

<em>150 miles</em>

Step-by-step explanation:

Given the scale on the map using the conversion factor

1 inch = 50 miles

We are to find the equivalent miles between the cities in miles if the distace is 3inches

3inches = x

Divide both expressions

1/3 = 50/x

Cross multiply

x = 3 * 50

x = 150

<em>Hence the actual distance between these two cities in miles is 150 miles </em>

6 0
3 years ago
A rectangular poster is 5 dm long and 3 dm wide. Sara wants to paint the whole poster. Find the area of the poster in square cm.
Zina [86]

Answer:

\boxed{1500cm^{2} }

Step-by-step explanation:

Area = Length × Width

→ Identify the length and width

Length = 5 and Width = 3

→ Substitute in the values

Area = 5 dm × 3 dm

→ Convert into cm

Area = 50 cm × 30 cm

→ Simplify

1500 cm²

6 0
3 years ago
Write an equation of the line in slope intercept form that pass through the two
Ber [7]
\bf \begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%   (a,b)&#10;&({{ -2}}\quad ,&{{ 15}})\quad &#10;%   (c,d)&#10;&({{ 9}}\quad ,&{{ -18}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies &#10;\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-18-15}{9-(-2)}\implies \cfrac{-18-15}{9+2}&#10;\\\\\\&#10;\cfrac{-33}{11}\implies -3

\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-15=-3[x-(-2)]&#10;\\\\\\&#10;y-15=-3(x+2)\implies y-15=-3x-6\implies y=-3x+9
8 0
3 years ago
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