O.99 m long .simple pendulum time period is 2s for second formula then use formula T=2pi.rt(lenght/gravity)
Answer:
Differences between freefall and weightlessness are as follows:
<h3>
<u>Freefall</u></h3>
- When a body falls only under the influence of gravity, it is called free fall.
- Freefall is not possible in absence of gravity.
- A body falling in a vacuum is an example of free fall.
<h3>
<u>Weightlessness</u></h3>
- Weightlessness is a condition at which the apparent weight of body becomes zero.
- Weightlessness is possible in absence of gravity.
- A man in a free falling lift is an example of weightlessness.
Hope this helps....
Good luck on your assignment....
Answer:
0.1 N
Explanation:
Considering the relationship between force,
spring constant and extension as defined by Hook's law
The force F=xk as from Hooke's law where F is the force of the spring, k is spring constant and x is extension or compression. Substituting 2 N/m for k and 5cm which is equivalent to 0.05 m for extention x then the force will be
F=2*0.05=0.1 N
Answer:
Explanation:
Given that
Length = L
At initial over hanging length = Xo
Lets take the length =X after time t
The velocity of length will become V
Now by energy conservation
So
We know that
At t= 0 ,X=Xo
So we can say that
So the length of cable after time t
Answer:
Explanation:
Electric field at the surface of the the lead 208 = KQ/ R²
where K = 8.99 × 10⁹ Nm² /C²
Q ( total charge inside the nucleus) and e is the charge of a proton = Ne = 82 × 1.6 × 10⁻¹⁹ C = 1.312 × 10⁻¹⁷ C
V of the lead = 208 v of a proton assuming they both are sphere
4/3 πR³ =208( 4/3 πr³) where R is the radius of the sphere and r is the radius of the proton
R³ = 208 r³
R = ∛( 208 r³) = 5.92r
replace r with 1.20 x 10-15 m
R = 5.92 ×1.20 x 10-15 m = 7.11 × 10⁻¹⁵ m
E = ( 8.99 × 10⁹ Nm² /C² × 1.312 × 10⁻¹⁷ C ) / (7.11 × 10⁻¹⁵ m)² = 0.233 × 10²² N/C = 2.33 × 10²¹ N/C
