1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andre [41]
3 years ago
13

Density, density, density. (a) A charge -312e is uniformly distributed along a circular arc of radius 5.70 cm, which subtends an

angle of 71o. What is the linear charge density along the arc? (b) A charge -312e is uniformly distributed over one face of a circular disk of radius 3.70 cm. What is the surface charge density over that face? (c) A charge -312e is uniformly distributed over the surface of a sphere of radius 4.20 cm. What is the surface charge density over that surface? (d) A charge -312e is uniformly spread through the volume of a sphere of radius 4.00 cm. What is the volume charge density in that sphere?
Physics
1 answer:
Katarina [22]3 years ago
4 0

Answer:

(a): Linear charge density of the circular arc = \rm -7.07\times 10^{-16}\ C/m.

(b): Surface charge density of the circular arc = \rm -1.16\times 10^{-14}\ C/m^2.

(c): Volume charge density of the sphere =  \rm -1.86\times 10^{-13}\ C/m^3.

Explanation:

<h2><u>Part (a):</u></h2>

<u>Given:</u>

  • Total charge on the circular arc, \rm q = -312\ e.
  • Radius of the circular arc, \rm r = 5.70\ cm = 0.057\ m.
  • Angle subtended by the circular arc, \rm \theta=71^\circ=71\times \dfrac{\pi }{180}\ rad = 1.23918\ rad.

We know, e is the elementary charge whose value is \rm 1.6\times 10^{-19}\ C.

Therefore, \rm q=-312\times1.6\times 10^{-19}=-4.992\times 10^{-17}\ C.

Also, the length l of a circular arc is given as:

\rm l = r\theta =0.057\times 1.23918=7.06\times 10^{-2}\ m.

The linear charge density \lambda of the arc is defined as the charge per unit length of the arc.

\rm \lambda = \dfrac{q}{l} = \dfrac{-4.992\times 10^{-17}}{7.06\times 10^{-2}}=-7.07\times 10^{-16}\ C/m.

<h2><u>Part (b):</u></h2>

<u>Given:</u>

  • Total charge on the circular disc, \rm q = -312\ e.
  • Radius of the circular disc, \rm r = 3.70\ cm = 0.037\ m.

\rm q=-312\times1.6\times 10^{-19}=-4.992\times 10^{-17}\ C.

Surface area of the circular disc, \rm A = \pi r^2 = \pi \times (0.037)^2 = 4.3\times 10^{-3}\ m^2.

The surface charge density \sigma of the disc is defined as the charge per unit area of the disc.

\rm \sigma = \dfrac qA=\dfrac{-4.992\times 10^{-17}}{4.3\times 10^{-3}}=-1.16\times 10^{-14}\ C/m^2.

<h2><u>Part (c):</u></h2>

<u>Given:</u>

  • Total charge on the sphere, \rm q = -312\ e.
  • Radius of the sphere, \rm r = 4.00\ cm = 0.04\ m.

\rm q=-312\times1.6\times 10^{-19}=-4.992\times 10^{-17}\ C.

Volume of the sphere, \rm V = \dfrac 43 \pi r^3 = \dfrac 43 \times \pi \times 0.04^3 = 2.68\times 10^{-4}\ m^3.

The volume charge density \rho of the sphere is defined as the charge per unit volume of the sphere.

\rm \rho = \dfrac qV = \dfrac{-4.992\times 10^{-17}}{ 2.68\times 10^{-4}}= -1.86\times 10^{-13}\ C/m^3.

You might be interested in
Important!
andreyandreev [35.5K]

Answer:

b

Explanation:

8 0
2 years ago
Please help!!! Thank you!!!!!
MrRa [10]
The amoeba is having a asexual reproduction and the two birds are not. The two birds are having a sexual reproduction.
7 0
3 years ago
Which kind of light is used to carry information through optical fibers?
ZanzabumX [31]
Red light would be commonly used due to the longer wavelength
3 0
3 years ago
Is eureka a better conductor than copper
cricket20 [7]
Nope Copper is a better conductor
5 0
3 years ago
Electric fish generate current with biological cells called electroplaques, which are physiological emf devices. The electroplaq
Harlamova29_29 [7]

Answer:

current in water = 0.924 A

Explanation:

Let the current in each row be i.

Thus, current in water is contributed by each row and total current in water becomes 140i.

We are given;

emf of each electroplaque = 0.15 V

Number of electroplaques = 5000

internal resistance = 0.25 Ω

resistance = 800Ω

Applying Kirchoff's Voltage Law to row and water, we have;

5000E − (5000r)i − 800(140i) = 0

Rearranging;

5000E = (5000r)i + 800(140i)

Plugging in the relevant values;

5000 x 0.15 = i((5000 x 0.25) + 112,000)

750 = 113,250i

i = 750/113,250

i = 0.0066 A

Recall earlier, the current in water is 140i.

Thus, current in water = 140 x 0.0066

= 0.924

5 0
2 years ago
Other questions:
  • A substance that is present in a solution in a smaller amount and is dissolved by the solvent is called the solute.
    9·1 answer
  • The picture below shows a soil texture triangle.
    5·1 answer
  • Starting with 100 grams of uranium-238, after one half life has gone by, how many grams of uranium-238 will remain?
    5·1 answer
  • Which three of these statements about current and voltage in a series circuit are true ?
    7·1 answer
  • a force of 20 N acted on a ball thereby imparting an impulse of 70 Ns to the ball. For how long did the force act on the ball?
    10·1 answer
  • Consider the waves on a vibrating guitar string and the sound waves the guitar produces in the surrounding air. The string waves
    7·1 answer
  • HURRY!!!!!!!
    6·2 answers
  • The portion of electromagnetic spectrum is occupied by signal is called ​
    15·1 answer
  • What type of wave is sound?<br> a. longitudnal<br> b. surface<br> c. tranverse,<br> or d.. light ? ?
    11·2 answers
  • 5. Find the velocity of a train that traveled 75 km in 35 minutes. (answer
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!