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andre [41]
3 years ago
13

Density, density, density. (a) A charge -312e is uniformly distributed along a circular arc of radius 5.70 cm, which subtends an

angle of 71o. What is the linear charge density along the arc? (b) A charge -312e is uniformly distributed over one face of a circular disk of radius 3.70 cm. What is the surface charge density over that face? (c) A charge -312e is uniformly distributed over the surface of a sphere of radius 4.20 cm. What is the surface charge density over that surface? (d) A charge -312e is uniformly spread through the volume of a sphere of radius 4.00 cm. What is the volume charge density in that sphere?
Physics
1 answer:
Katarina [22]3 years ago
4 0

Answer:

(a): Linear charge density of the circular arc = \rm -7.07\times 10^{-16}\ C/m.

(b): Surface charge density of the circular arc = \rm -1.16\times 10^{-14}\ C/m^2.

(c): Volume charge density of the sphere =  \rm -1.86\times 10^{-13}\ C/m^3.

Explanation:

<h2><u>Part (a):</u></h2>

<u>Given:</u>

  • Total charge on the circular arc, \rm q = -312\ e.
  • Radius of the circular arc, \rm r = 5.70\ cm = 0.057\ m.
  • Angle subtended by the circular arc, \rm \theta=71^\circ=71\times \dfrac{\pi }{180}\ rad = 1.23918\ rad.

We know, e is the elementary charge whose value is \rm 1.6\times 10^{-19}\ C.

Therefore, \rm q=-312\times1.6\times 10^{-19}=-4.992\times 10^{-17}\ C.

Also, the length l of a circular arc is given as:

\rm l = r\theta =0.057\times 1.23918=7.06\times 10^{-2}\ m.

The linear charge density \lambda of the arc is defined as the charge per unit length of the arc.

\rm \lambda = \dfrac{q}{l} = \dfrac{-4.992\times 10^{-17}}{7.06\times 10^{-2}}=-7.07\times 10^{-16}\ C/m.

<h2><u>Part (b):</u></h2>

<u>Given:</u>

  • Total charge on the circular disc, \rm q = -312\ e.
  • Radius of the circular disc, \rm r = 3.70\ cm = 0.037\ m.

\rm q=-312\times1.6\times 10^{-19}=-4.992\times 10^{-17}\ C.

Surface area of the circular disc, \rm A = \pi r^2 = \pi \times (0.037)^2 = 4.3\times 10^{-3}\ m^2.

The surface charge density \sigma of the disc is defined as the charge per unit area of the disc.

\rm \sigma = \dfrac qA=\dfrac{-4.992\times 10^{-17}}{4.3\times 10^{-3}}=-1.16\times 10^{-14}\ C/m^2.

<h2><u>Part (c):</u></h2>

<u>Given:</u>

  • Total charge on the sphere, \rm q = -312\ e.
  • Radius of the sphere, \rm r = 4.00\ cm = 0.04\ m.

\rm q=-312\times1.6\times 10^{-19}=-4.992\times 10^{-17}\ C.

Volume of the sphere, \rm V = \dfrac 43 \pi r^3 = \dfrac 43 \times \pi \times 0.04^3 = 2.68\times 10^{-4}\ m^3.

The volume charge density \rho of the sphere is defined as the charge per unit volume of the sphere.

\rm \rho = \dfrac qV = \dfrac{-4.992\times 10^{-17}}{ 2.68\times 10^{-4}}= -1.86\times 10^{-13}\ C/m^3.

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