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2 years ago

Simon makes eleven dollars an hour.

Mathematics

2 answers:

Citrus2011 [14]2 years ago

6 0

Answer:

d=11 the number of hours the number of dollars

Step-by-step explanation:

right on egde 2020

ElenaW [278]2 years ago

6 0

Answer:

The other person is correct!!

Step-by-step explanation:

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30000 is blank times as much as 30

Sindrei [870]

1000 is the answer !

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2 years ago

Read 2 more answers

Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .

sergey [27]

Step 1) Divide the figure into separate shapes

Long rectangle: 27 x 5

Triangle: 3 x 4

Middle rectangle: 15 x 7

Small rectangle: 6 x 3

Step 2) Find the area of each shape

Long rectangle: A = 27 x 5 = 135

Triangle: A = 1/2 x 3 x 4 = 6

Middle rectangle: A = 15 x 7 = 105

Small rectangle: 6 x 3 = 18

Step 3) Add all of the areas together

A = 135 + 6 + 105 + 18 = 264 square feet

Hope this helps! :)

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3 years ago

Identify the volume and surface area of the hemisphere in terms of π. HELP ASAP!!

posledela

Answer:

Step-by-step explanation:

Use the formula for the SA of a hemisphere.

$SA=2\pi r^2$

Now we can find the radius of the hemisphere, which is 15.

Then, we can square that and multiply it by 2 to get 450.

Now, let's use the formula for the Volume of a hemisphere.

$V=\frac{2\pi r^3}{3}$

Now we can cube 15 and multiply it by 2 to get 6750.

Then we can divide this number by 3.

2250.

So the answer is D.

4 0

3 years ago

If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w

MatroZZZ [7]

Let $x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11}$ be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

$\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.$

2. If the mean weight of the 7 other players is 202 lb, then

$\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.$

3. From the previous statements you have that

$x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.$

Add these two equalities and then divide by 11:

$x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.$

Answer: the mean weight of the 11-person team is $208\dfrac{10}{11}\ lb.$

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2 years ago