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pantera1 [17]
3 years ago
6

Can someone help me with these 3 questions please and thank you

Chemistry
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

1 i would find a way out of the unsafe situation and get away

2 not really to much

3 take care of each other and care for one another

Explanation:

there is my answers please be happy i am only in middle school so that is the best i can do for you.

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When a ball is rolling down a hill, what forces are acting on the ball? Why does it speed up?
Margaret [11]

Answer:gravity

Explanation:

3 0
3 years ago
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hat is the product when magnesium reacts with nitrogen? Mg(s) + N2(g) → Mg2N3(s) Mg3N(s) Mg3N2(s) MgN3(s)
Ipatiy [6.2K]
3Mg + N₂ = Mg₃N₂

Mg₃N₂
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5 0
3 years ago
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Given the two reactions H2S(aq)⇌HS−(aq)+H+(aq), K1 = 9.57×10−8, and HS−(aq)⇌S2−(aq)+H+(aq), K2 = 1.46×10−19, what is the equilib
Dvinal [7]

<u>Answer:</u> The value of K_c for the final reaction is 7.16\times 10^{25}

<u>Explanation:</u>

The given chemical equations follows:

<u>Equation 1:</u>  H_2S(aq.)\rightleftharpoons HS^-(aq.)+H^(aq.);K_1

<u>Equation 2:</u>  HS^-(aq.)\rightleftharpoons S^{2-}(aq.)+H^(aq.);K_2

The net equation follows:

S^{2-}(aq.)+2H^+(aq.)\rightleftharpoons H_2S(aq.);K_c

As, the net reaction is the result of the addition of reverse of first equation and the reverse of second equation. So, the equilibrium constant for the net reaction will be the multiplication of inverse of first equilibrium constant and the inverse of second equilibrium constant.

The value of equilibrium constant for net reaction is:

K_c=\frac{1}{K_1}\times \frac{1}{K_2}

We are given:

K_1=9.57\times 10^{-8}

K_2=1.46\times 10^{-19}

Putting values in above equation, we get:

K_c=\frac{1}{(9.57\times 10^{-8})}\times \frac{1}{(1.46\times 10^{-19})}=7.16\times 10^{25}

Hence, the value of K_c for the final reaction is 7.16\times 10^{25}

5 0
3 years ago
Calculate the volume in mL of 0.589 M NaOH needed to neutralize 52.1 mL of 0.821 M HCl in a titration.
Igoryamba

Answer:

72.6 mL

Explanation:

A quick way to solve this titration problem when you have a monoprotic acid is to use the Dilution equation, M1V1=M2V2.

.589(x)=.821(52.1)

X=72.6 mL

4 0
3 years ago
(reporting links) giving brainly
castortr0y [4]

Answer:

B.

Explanation:

B. low temperature, high dissolved oxygen, and neutral pH

Hope this Helps.

5 0
3 years ago
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