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NemiM [27]
2 years ago
13

If your client receives a letter from SilverScript requesting proof of Creditable Coverage, and the client has already submitted

proof of creditable coverage with the enrollment application, they can ignore the letter.
Chemistry
1 answer:
KatRina [158]2 years ago
8 0

If your client receives a letter from SilverScript requesting proof of Creditable Coverage, they can ignore the letter is a false statement

<h3>What is Creditable coverage?</h3>

Creditable coverage is known to be a form of an health insurance, that consist of prescription drug and also other kinds of health benefit plan that is known to meets  the minimum amount of qualifications.

Note that  the types of creditable coverage plans are group and individual health plans, student health plans,  and others.

It is not right to ignore any letter sent to you concerning the case above as it may be vital and as such, the statement of If your client receives a letter from SilverScript requesting proof of Creditable Coverage, and the client has already submitted proof of creditable coverage with the enrollment application, they can ignore the letter is a wrong/false statement.

Learn more about Creditable Coverage from

brainly.com/question/14547867

#SPJ1

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An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure, and temperature were 94 mL,
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Answer : The initial volume was, 71.2 mL

Explanation :

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1,V_1\text{ and }T_1 are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2 are the final pressure, volume and temperature of the gas

We are given:

P_1=0.85atm\\V_1=?\\T_1=66^oC=[66+273]K=339K\\P_2=0.60atm\\V_2=94mL\\T_2=43^oC=[43+273]K=316K

Now put all the given values in above equation, we get:

\frac{0.85atm\times V_1}{339K}=\frac{0.60atm\times 94mL}{316K}

V_1=71.2mL

Therefore, the initial volume was, 71.2 mL

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