A student made the Lewis dot diagram of a compound as shown.
2 answers:
Answer : The correct option is, (2) Both electrons of Mg should be transferred to one O because the formula is MgO.
Explanation :
Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.
Ionic compound are usually formed when a metal reacts with a non-metal.
Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.
The covalent compound are usually formed when two non-metals react.
As we know that the magnesium is an alkali metal and has 2 valence electron and oxygen is a non-metal and has 6 valence electrons.
As we know that magnesium atom can donates 2 electrons to a oxygen atom to complete an octet then it forms an ionic compound that is magnesium oxide (MgO).
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The given molecule is,
Therefore, the total number of valence electrons in = 2 + 6 = 8
According to Lewis-dot structure, there are 2 number of bonding electrons and 6 number of non-bonding electrons.
Hence, the correct option is, (2) Both electrons of Mg should be transferred to one O because the formula is MgO.
You might be interested in
Answer:
Answer: a) 20g of H2O (18.02 g/mol) molecules=6.68x10^23
Explanation:
In order to find the amount of molecules of each of the options, we need to follow the following equation.
So, let´s get the number of molecules for each of the options.
the smalest number is in option a)
Best of luck.
The percentage of Chromium in Chromium Oxide is calculated as follow,
Step 1:
Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
O = 16 u
So,
2(51.99) + 3(16) = 103.98 + 48 = 151.98 u
Step 2:
Secondly divide molar mass of only chromium with total mass of Cr₂O₃ and multiply with 100.
i.e.
=
× 100
= 68.41 %
So, the %age composition of chromium in chromium oxide is 68.41 %.
Step 1:
Calculate Molar mass of Cr₂O₃,
Cr = 51.99 u
O = 16 u
So,
2(51.99) + 3(16) = 103.98 + 48 = 151.98 u
Step 2:
Secondly divide molar mass of only chromium with total mass of Cr₂O₃ and multiply with 100.
i.e.
=
= 68.41 %
So, the %age composition of chromium in chromium oxide is 68.41 %.