All categories

3 years ago

A student made the Lewis dot diagram of a compound as shown.

Chemistry

2 answers:

Dovator [93]3 years ago

8 0

Answer : The correct option is, (2) Both electrons of Mg should be transferred to one O because the formula is MgO.

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

As we know that the magnesium is an alkali metal and has 2 valence electron and oxygen is a non-metal and has 6 valence electrons.

As we know that magnesium atom can donates 2 electrons to a oxygen atom to complete an octet then it forms an ionic compound that is magnesium oxide (MgO).

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is, $MgO$

Therefore, the total number of valence electrons in $MgO$ = 2 + 6 = 8

According to Lewis-dot structure, there are 2 number of bonding electrons and 6 number of non-bonding electrons.

Hence, the correct option is, (2) Both electrons of Mg should be transferred to one O because the formula is MgO.

Anton [14]3 years ago

4 0

Answer:

the answer is number 2

Explanation:

You might be interested in

A galvanic^cell consists of left ompartmcnt with a tin elcctrode in contact with 0.1 M Sn(NO_3)_2(aq) and a right compartment wi

lana66690 [7]

Answer:

Electrons will flow from left to right through the wire.

Pb^2+ ions will be reduccd to Pb metal.

The concentration of Sn2+ ions in the left compartment will increase.

Explanation:

Looking at the relative electrode potentials of the two metals

Sn= -0.14

Pb=-0.13

Tin is expected to function as the anode (left hand half cell) and lead as the anode (right hand half cell) tin oxidizes to sn^2+ hence its concentration increases on the left compartment while lead is reduced to ordinary lead metal on the right hand half cell . since oxidation occurs on the left hand side, electrons flow from left to right.

6 0

3 years ago

You are preparing some solutions for your instructor and have been asked to prepare 3.00 L of a 0.250M sodium hydroxide solution

grigory [225]

Answer:

C. 30.0 g NaOH and add water until the final solution has a volume of 3.00 L.

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

from the question ,

M = 0.250M

V = 3.00 L

M = n / V

n = M * v

n = 0.250M * 3.00 L = 0.75 mol

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

n = 0.75 mol NaOH

m = molecular mass of NaOH = 40 g/mol

n = w / m

w = n * m

w = 0.75 mol * 40 g/mol = 30.0 g

Hence , by using 30.0 g of NaOH and dissolving it to make up the volume to 3 L , a solution of 0.250 M can be prepared .

4 0

3 years ago

4 points

musickatia [10]

Divide mass by density to determine volume. 115.384 cm^3 (unsure if you need to round.)

7 0

3 years ago

What is the coefficient for the oxygen molecule in the chemical equation below? 2hgo → 2hg + ? o2?

Alecsey [184]

This question is purely balancing the chemical equation where the number of atoms in reactants is equal to the number of atoms in products.
For the mentioned equation:
In the reactants, we have 2 atoms of Hg and 2 atoms of oxygen.
In the products, we should have 2 atoms of Hg and 2 atoms of oxygen.
Since the oxygen molecule is composed of 2 oxygen atoms, therefore the coefficient should be equal to 1 for the equation to be balanced.

7 0

3 years ago

Use the periodic table to determine what element cesium-135 () becomes after beta decay.

bonufazy [111]

Answer:

D. $_{56}^{135}\text{Ba}$

Explanation:

Your unbalanced nuclear equation is

$_{55}^{135}\text{Cs} \longrightarrow ? + _{-1}^{0}\text{e}$

It is convenient to replace the question mark by an atomic symbol, $_{x}^{y}\text{Z}$ , where x = the atomic number, y = the mass number, and Z = the symbol of the element .

Then your equation becomes

$_{55}^{135}\text{Cs} \longrightarrow _{x}^{y}\text{Z} + _{-1}^{0}\text {e}$

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.

Then

55 = x - 1, so x = 55 + 1 = 56

135 = y + 0, so y = 135

Element 56 is barium, so the nuclear equation becomes

$_{55}^{135}\text{Cs} \longrightarrow _{56}^{135}\text{Ba} + _{-1}^{0}\text{e}$

4 0

3 years ago

Read 2 more answers