A student made the Lewis dot diagram of a compound as shown.
2 answers:
Answer : The correct option is, (2) Both electrons of Mg should be transferred to one O because the formula is MgO.
Explanation :
Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.
Ionic compound are usually formed when a metal reacts with a non-metal.
Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.
The covalent compound are usually formed when two non-metals react.
As we know that the magnesium is an alkali metal and has 2 valence electron and oxygen is a non-metal and has 6 valence electrons.
As we know that magnesium atom can donates 2 electrons to a oxygen atom to complete an octet then it forms an ionic compound that is magnesium oxide (MgO).
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The given molecule is,
Therefore, the total number of valence electrons in = 2 + 6 = 8
According to Lewis-dot structure, there are 2 number of bonding electrons and 6 number of non-bonding electrons.
Hence, the correct option is, (2) Both electrons of Mg should be transferred to one O because the formula is MgO.
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Answer:
The mass of PbSO4 formed 15.163 gram
Explanation:
mole of Pb(NO₃)₂ = 1.25 x 0.05 = 0.0625
mole of Na₂SO₄ = 2 x 0.025 = 0.05
Pb(NO₃)₂ + Na₂SO₄ → PbSO₄ + 2 NaNO₃
( Mole/Stoichiometry )
= 0.0625 = 0.05
From (Mole/ Stoichiometry ) we can conclude that Na₂SO₄ is limiting reagent.
Mass of PbSO₄ precipitate = 0.05 x Molecular mass of PbSO₄
= 0.05 x 303.26 g
= 15.163 g