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Natali5045456 [20]
4 years ago
6

How would a system in which both matter and energy are exchanged freely between the system and the surroundings be classified?

Chemistry
2 answers:
Orlov [11]4 years ago
7 0
The answer should be a closed system
Zanzabum4 years ago
4 0

Answer:  Open System

Explanation:   System can be classified into 3 types-

a) Open System - In this kind of system, matter and energy both are exchanged freely with the surroundings.

Example - A tea in a container with the open lid.

b) Closed System - In this kind of system, matter cannot be exchanged but energy can be exchange with the surroundings.

Example - A tea in the container with closed lid.

c) Isolated System - In this, neither energy or matter can be exchanged with the surroundings.

Example - A tea in an insulated thermal flask.

Thus the system in which matter and energy are exhanged freely between the syste and the surroundings is classiifed as Open System.

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What volume (l) of 0.750 m kcl solution contains 25.0 g of kcl?
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Conc = moles / Vol you have C but need to find moles 
moles KCl = mass / molar mass 
25 g / 74.55 g,p; 
0.335 moles 
So rearrange the formula to find volume. Vol = moles / Conc 
0.335 moles / 0.750 mol / L = 0.447 L or 447 mL

The answer in this question is 447 mL.
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3 years ago
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4 years ago
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Describe what a moraine is made of and explain how this glacial feature forms.
guajiro [1.7K]

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On quizlet

5 0
3 years ago
Please help I’m timed !!!
Rashid [163]

Answer:

b. \% diss =4.4x10^{-2}\%

Explanation:

Hello there!

In this case, given the ionization reaction of HClO as weak acid:

HClO\rightleftharpoons H^++ClO^-

We can write the equilibrium expression as shown below:

Ka=3.5x10^{-8}=\frac{[H^+][ClO^-]}{[HClO]}

In such a way, via the definition of x as the reaction extent, we can write:

3.5x10^{-8}=\frac{x^2}{[HClO]}

As long as Ka<<<<1 so that the x on the bottom can be neglected. Thus, we solve for x as shown below:

x=\sqrt{3.5x10^{-8}*0.18} =\\\\x=7.94x10^{-5}M

And finally the percent dissociation:

\% diss=\frac{x}{[HClO]} *100\%\\\\\% diss=\frac{7.94x10^{-5}M}{0.18}*100\% \\\\\% diss =0.044\%=4.4x10^{-2}\%

Which is choice b.

Best regards!

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