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zhuklara [117]
3 years ago
6

An atom of chlorine with a mass number of 37 contains __ protons and __ neutrons.

Chemistry
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer:

Its in the Explanation

Explanation:

Here's what I got.

Aluminium-27 is an isotope of aluminium characterized by the fact that is has a mass number equal to  

27

.

Now, an atom's mass number tells you the total number of protons and of neutrons that atom has in its nucleus. Since you're dealing with an isotope of aluminum, it follows that this atom must have the exact same number of protons in its nucleus.

The number of protons an atom has in its nucleus is given by the atomic number. A quick looks in the periodic table will show that aluminum has an atomic number equal to  

13

.

This means that any atom that is an isotope of aluminum will have  

13

protons in its nucleus.

Since you're dealing with a neutral atom, the number of electrons that surround the nucleus must be equal to the number of protons found in the nucleus.

Therefore, the aluminium-27 isotope will have  

13

electrons surrounding its nucleus.

Finally, use the known mass number to determine how many neutrons you have

mass number

=

no. of protons

+

no. of neutrons

no. of neutrons = 27 − 13 = 14

Your welcome :)

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Desert plants work hard to make use of what's available. They use the sun's energy to convert carbon dioxide (CO2) and water (H2O) into sugar, a process called photosynthesis. During this process, stomata on a plant's leaves and stems open to absorb carbon dioxide from the air and in return release oxygen. :)
4 0
3 years ago
Read 2 more answers
30.0 grams of NaNO3 is dissolved in water to make a 5.00 L solution. What is the molarity of the solution?
Morgarella [4.7K]

Answer:

Molarity= 0.071M

Explanation:

Molar mass of NaNO3= 23+14+(16*3)=85

n= m/M = 30/85= 0.353mol

V= 5L

Applying

n= CV

0.353= C×5

Simplify

C= 0.071M

4 0
3 years ago
What is the empirical formula of a carbon-oxygen compound, given that a 95.2 g sample of the compound contains 40.8 g of carbon
algol [13]

Answer:

95.2 - 40.8 = 54.4 g of oxygen

number of moles = mass (g)/ Mr

no. of moles of carbon = 40.8/12 = 3.4

no. of moles of oxygen = 3.4

divide both by smallest value which is 3.4 and you’ll get 1 mole of carbon and 1 mole of oxygen therefore the empirical formula is CO

Explanation:

hope this helps :)

4 0
3 years ago
Scientific predictions based on laws are formulated using:
abruzzese [7]

Answer:

A. deductive reasoning

7 0
4 years ago
Read 2 more answers
How much water needs to be added
Olegator [25]

Answer:

165 ml

Explanation:

We are given;

Initial volume; V_a = 55 ml

Initial molarity; M_a = 3 M

Molarity of desired solution; M_b = 0.75 M

Volume of desired solution; V_b = (55 + x) ml

Where x is the volume of water to be added.

To solve for V_b, we will use the equation ;

M_a•V_a = M_b•V_b

V_b = (M_a•V_a)/M_b

V_b = (3 × 55)/0.75

V_b = 220 mL

Thus;

(55 + x) = 220

x = 220 - 55

x = 165 mL

8 0
3 years ago
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