By solving the system by substitution, we got the solutions:
x = 2/3, y = 8/3.
<h3>
Solving the system of equations:</h3>
I guess we need to solve problem number 5, so let's do that.
Here we have the system of equations:
y = x + 2
3x + 3y = 6
To solve it by substitution, we need to isolate one of the variables in one of the equations and then replace that in the other equation.
For example, here we can see that "y" is already isolated in the first equation, so we can use that and replace it in the second equation.
3x + 3y = 6
3x + 3*(y = x + 2) = 6
3x + 3*(x + 2) = 6
Now we have an equation that only depends on x, so we can solve it:
3x + 3x + 2 = 6
6x + 2 = 6
6x = 6 - 2 = 4
x = 4/6 = 2/3.
Now we can use the first equation to find the value of y:
y = x + 2 = 2/3 + 2 = 2/3 + 6/3 = 8/3.
Then the solution is:
x = 2/3 and y = 8/3.
If you want to learn more about systems of equations, you can read:
brainly.com/question/13729904
Assuming you mean the area is 28 yd², equations for the length (y) and width (x) can be written:
These equations can be solved by a variety of means. One I like is graphing. A graphing calculator tells you the solution is (width, length) = (3.5 yd, 8 yd).
Answer:
on like term
Step-by-step explanation:
x+2)=(y-5)=2+5=7
x-y{x-y]=7x-y
by Emmanuel okorie
Answer:
20.3 cm. to the nearest tenth.
Step-by-step explanation:
Using the Pythagoras Theorem:
CR^2 = CS^2 + SR^2
= 6^2 + 13^2
= 205
CR = √205 cm.
UR = CR (because they are both radii of the circle).
So UR = √205
and SU =6 + √205
= 20.3 cm to the nearest tenth.
