The ratio of the area of ∆ABC to the area of ∆DEF is; 1:100.
<h3>What is the ratio of the area of ∆ABC to the area of ∆DEF?</h3>
Since, a major criterion for similarity and congruence of triangles is that the ratio of corresponding sides are equal.
On this note, since the task content suggest that the ratio of the perimeters is; 1:10, it follows from conventional mathematics that the ratio of their areas is given as; 1²:10²; 1:100.
Read more on congruent triangles;
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Answer: the answer is really -8 (A)
Step-by-step explanation: because how do 0 make since u can't divide 3x and -8
Answer:
<h3>
X∈∅</h3>
Step-by-step explanation:
Answer:
12+m
a25
Step-by-step explanation:
Ill answer more if im given brainliest
Hancock building * .27 = 92 m
divide each side by .27
Hancock building =92/.27
Hancock building =340.740(repeating)
Answer: the building is approximately 340.74 meters
