Vertex: (3,-65) axis of Symmetry: x = 3
What is the measure of ACB in O below?
1 answer:
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So what you do is
make into ax^2+bx+c=0 form
add-9/2 to both sides
y^2-2y+9/2=0
now we use the quadratice formula which is
x=
ax^2+bx+c=0
1y^2-2y+9/2
a=1
b=-2
c=9/2
subsitute
x=
x=
x=
x=
x=
x=
x=
x=
x=
answer is C
make into ax^2+bx+c=0 form
add-9/2 to both sides
y^2-2y+9/2=0
now we use the quadratice formula which is
x=
ax^2+bx+c=0
1y^2-2y+9/2
a=1
b=-2
c=9/2
subsitute
x=
x=
x=
x=
x=
x=
x=
x=
x=
answer is C