Answer:
Step-by-step explanation:
All other things being equal (and there are a lot of other things) the 50 gram mass will show a larger temperature
increase than the 100 gram mass.
Why?
The formula is the same from both masses of water (50 grams and 100 grams)
The amount of heat added is the same. (Instead of using hot water, we'll a hot plate on a very low temperature but above what they are now.).
We'll leave it on until we see a rise in temperature delta(t1) = 10 degrees
mc delta(t) = m1 * c * delta(t1)
m = 100
m1 = 50 grams.
c is going to be divided out
we'll solve for the ratio of delta(t) / delta(t1)
100 * delta(t) = 50 (delta(t1)
100 * delta(t) = 50*10
delta(t) = 50*10/100
delta(t) = 5 degrees.
Though this may look rather convoluted, the result is telling us is that delta(t1) for the 50 gram mass is twice as big as as for the 100 gram mass.
The 100 gram mass only rises 5 degrees.
The 50 gram mass rises 10 degrees.
Square roots the square root of 1 is one square root of 2 is 4 square root of 3 is 9 and ect.
Answer:
8x+4 and 10x+4
Step-by-step explanation:
Using the distributive property, you times 8 by x and then 8 by one half: 8x & 8*1/2. 8x+4
You then do the same for 10(x+2/5): 10x and then 10 divided by 5 and times by 2. This leaves you with 10x+4.
I hope this helped. :)
The attachment is cut in half
