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2 years ago

What triangles are similar to triangle AED? Explain or show your reasoning.

Mathematics

1 answer:

VLD [36.1K]2 years ago

4 0

Answer:

DCE is similar to AED

EBA is similar to AED

AFE is similar to AED

EFD is similar to AED

Step-by-step explanation:

Triangle AED:

D=53(alternate interior angle)

A=180-90-53=37 (angle of triangle)

AA similarity criterion

DCE is similar to AED

angle BEA=180-90-53=37=angle A of AED

Thus: AA similarity criterion:

EBA is similar to AED

The diagonal of parallelogram(here:rectangle) cut it into 2 congruent triangles

Thus:

EBA is congruent to AFE

EBA is congruent to AFEDCE is congruent to EFD

Congruent triangles are similar

Conclusion:

DCE is similar to AED

EBA is similar to AED

AFE is similar to AED

EFD is similar to AED

Please give brainliest if it helps

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lisabon 2012 [21]

Given the following functions below,

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Factorising the denominators of both functions,

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$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

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1 year ago

Math help @LIEMONDER

klio [65]

First picture)
I: 5x+2y=-4
II: -3x+2y=12

add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
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insert x=-2 into I:
5*(-2)+2y=-4
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(-2,3)

question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
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insert childs into I:
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so it's the last option

question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
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question 8)
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Answer:

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Answer:

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Step-by-step explanation:

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$SA=4\pi r^2$

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Round the result to the nearest whole number:

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Picture:

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