Answer:
f(x) > 0 over the interval 
Step-by-step explanation:
If f(x) is a continuous function, and that all the critical points of behavior change are described by the given information, then we can say that the function crossed the x axis to reach a minimum value of -12 at the point x=-2.5, then as x increases it ascends to a maximum value of -3 for x = 0 (which is also its y-axis crossing) and therefore probably a local maximum.
Then the function was above the x axis (larger than zero) from
, until it crossed the x axis (becoming then negative) at the point x = -4. So the function was positive (larger than zero) in such interval.
There is no such type of unique assertion regarding the positive or negative value of the function when one extends the interval from
to -3, since between the values -4 and -3 the function adopts negative values.
To find the discount of an item you put the rate which is 25% over 100 and move the decimal point to the right this would leave you with 0.25.You then times $40 by 0.25 which leaves you with $10 so $10 is your discount.
To find the sales price of the dress you subtract the discounted price from the original price so it would be $40-$10 which is $30 so your sales price is $30.
46, 16 is a little less than 1/2 of 34, so and 46 is a little less than 1/2 of 100.
Answer:
Slide 1:
1. Solution = (-3,2)
<em>y = 2x - 1</em>
<em>y = 3/2x + 6</em>
2. No solution
<em>y = -4/2x + 4</em>
<em>y = -4/2x - 5</em>
Slide 2:
3. Solution = (1, -6) ONE SOLUTION
4. Solution = (-4, -1) ONE SOLUTION
p.s i attached the graphs for problems 3 and 4. The first picture is for problem 3 and the second picture is for problem 4
I really hope this helped :)
Brayden has 38 bags.
After giving away 15 bags of marbles, Brayden is left with 23 bags.
To find out how many bags he has we do 342 divided by 9 which is 38.
To find out how many marbles are in 15 bags we do 15 x 9 which is 135.
We then do 342 - 135 to find out how many marbles he has left which is 207 and divide 207 by 9 to convert that into bags, which is 23.