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never [62]
3 years ago
11

HALP ME I'M FAILING :,O

Mathematics
1 answer:
kkurt [141]3 years ago
3 0

Answer:

D

Step-by-step explanation:

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Please help !<br> I need the answers for #43 and #44
Vlad [161]

43. 9 + 10 + 13 + 13 = $45

45 - 1 = 44

44 x 4 = 176

176 + 8 = 184

184/4 = 46

46 tokens per person

44. a. 22 x 5 = 110

943/110 = 8.7

you will need 9 bookcases

b. 110 x 9 = 990

990 - 943 = 47

47 - 44 = 3

There will be 3 books on the third shelf.

4 0
3 years ago
the lenght of a rectangle is 2 cm less than 7 times the width. the perimeter is 60 cm . find the width and lenght
vampirchik [111]
First, you want to establish your equations.

L=7W-2
P=60

This is what we already know. To find the width, we have to plug in what we know into P=2(L+W), our equation to find perimeter.

60=2(7W-2+W)

Now that we only have 1 variable, we can solve.

First, distribute the 2.
60=14W-4+2W

Next, combine like terms.

60=16W-4

Then, add four to both sides.

64=16W

Lastly, divide both sides by 16


W=4

To find the length, we plug in our width.

7W-2

7(4)-2

28-2

L=26
8 0
3 years ago
A withdrawal of $50 is negative or positive?
prisoha [69]
A withdrawal of $50 is negative because you are taking money out of your account and your money in your account is getting less than what it was before.
8 0
3 years ago
Read 2 more answers
What are all of the real roots of the following polynomial? f(x) x^4-24x^2-25
Greeley [361]

<u>Answer:</u>

x = ±5

<u>Step-by-step explanation:</u>

We are given the following polynomial function and we are to find all of its real roots:

x^4-24x^2-25

Let y=x^2 so we can now write it as:

y^2-24y-25

Factorizing it to get:

(y^2+y)+(-25y-25)

y\left(y+1\right)-25\left(y+1\right)

\left ( y + 1 \right ) \left ( y - 2 5 \right)

Substitute back y=x^2 to get:

\left ( x^2 + 1 \right ) \left ( x^2 - 25 \right )

\left ( x^2 + 1 \right ) \left ( x + 5 \right ) \left ( x - 5 \right )

The quadratic factor has only complex roots. Therefore, the real roots are x = ±5.

3 0
4 years ago
Read 2 more answers
Find y' by implicit differentiation: xy + 2x + 3x^2 = 4
NeX [460]
(xy)' + (2x)' + (3x^2)' = (4)'

y + xy' + 2 + 6x = 0

xy' = -y  -2 -6x

y' = [-y -2 -6x] / x

Now solve y from the original equation and substitue

xy + 2x + 3x^2 = 4 => y = [-2x - 3x^2 + 4] / x

y' =  [(-2x - 3x^2 +4) / x - 2 - 6x ] / x

y' = [-2x - 3x^2 + 4 -2x -6x^2 ] x^2 = [ -4x - 9x^2 + 4] / x^2 =

= [-9x^2 - 4x + 4] / x^2
3 0
3 years ago
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