Atoms and protons are tricking. they snicks and twix
recall in a perfect square trinomial, the middle term is the tale-tell guy, we know the middle term is the product of 2 and the two other guys without the exponent, so in this case 6x = 2*√x² * √c.

First of all, you need to come to an understanding of what you mean by "compare that score to the population." Often, that will mean determining the percentile rank of the score.
To determine the percentile rank of a raw score, you first nomalize it by determining the number of standard deviations it lies from the mean. That is, you subtract the population mean and divide that difference by the population standard deviation. Now, you have what is referred to as a "z-score".
Using a table of standard normal probability functions (or an equivalent calculator or app), you look up the cumulative distribution value corresponding to the z-score you have. This number between 0 and 1 (0% and 100%) will be the percentile rank of the score, the fraction of the population that has raw scores below the raw score you started with.
Answer:
square units.
Step-by-step explanation:
We have to use limits to find the area of the region bounded by the graph
, the x-axis, and the vertical lines x=0 and x=1.
So, the area will be
A = 
= ![[4x - \frac{x^{4}}{2} ]^{1} _{0}](https://tex.z-dn.net/?f=%5B4x%20-%20%5Cfrac%7Bx%5E%7B4%7D%7D%7B2%7D%20%5D%5E%7B1%7D%20_%7B0%7D)
= 
=
square units. (Answer)
Answer:
A.) 6.0
Step-by-step explanation:
I dont explain very well, but..
if the next number is above or it is 5, then u round up