-4 = r/20 -5Solve for r. Show your steps
2 answers:
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Answer:
Step-by-step explanation:
In order to do this, you have to know how to use your calculator's regression equation function.
First enter in the data. Hit "stat" then 1:Edit and enter all the x values into L1. After each value, hit enter. When you're done with the x list, arrow over to L2 and enter in all the y-values. If there are already values there you need to clear, arrow up to highlight L1, hit "clear", then "enter" and the values will disappear. Do that for both lists if you need to.
After the data is listed in L1 and L2, hit "stat" again and arrow over to "Calc". Hit 5:QuadReg. If you have a TI 83, your equation will be there for you. If you have a TI 84, you'll need to arrow down to "calculate" to get the equation. Regardless, the equation is
, the last choice in your options.
<h3>1. Inscribe a circle ΔJKL. Identify the point of concurrency that is the center of the circle you drew. </h3>
<h3>2. Circumscribe a circle ΔFGH. Identify the point of concurrency that is the center of the circle you drew. </h3>
To inscribe a circle in the attached triangle, we must follow the following steps. The resultant figure is the first one below.
1. Draw the angle bisector of angle JKL. The straight line in the green one.
2. Draw the angle bisector of angle KLJ. The straight line in the blue one.
3. Draw point D at these two lines.
4. Draw a line through point D perpendicular to side JK. The straight line in the red one.
5. Mark point G at the red line and side JK.
6. Draw a circle with center at D (point of concurrency) and a radius of DG.
<h3>2. Circumscribe a circle ΔFGH. Identify the point of concurrency that is the center of the circle you drew. </h3>
To circumscribe a circle in the attached triangle, we must follow the following steps:
1. Draw the perpendicular bisector of the side FG. The straight line in the red one. The resultant figure is the second one below.
2. Draw the perpendicular bisector of the side GH. The straight line in the blue one.
3. The center of the circle is the intersection of these two lines
4. Draw a circle with center at D (point of concurrency).
<h3>3. Construct the two lines tangents to circle</h3>A tangent to a circle is a straight line that touches the circle at an only point. If a point A is outside a circle, we can draw two lines that pass through this point and are tangent to the circle at two different points each. So this is shown in the third figure. Lines red and blue are tangent to the circle at two different points.