The applications that will involve percentages include:
- Sales Tax
- Original Sale Price
- Commission
- Income Tax
<h3>Which applications involve percentages?</h3>
Sales tax will involve percentage because the sales tax percentage will be needed to calculate the sales tax. The same goes for the income tax.
Commissions also involve percentages as the commission is a percentage of sales. The original sales price can only be acquired by using the discount or markup percentage applied to it to get the current sales price.
Find out examples of commission percentages at brainly.com/question/24951536.
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Step-by-step explanation:
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:<span> </span><span>You need to know the derivative of the sqrt function. Remember that sqrt(x) = x^(1/2), and that (d x^a)/(dx) = a x^(a-1). So (d sqrt(x))/(dx) = (d x^(1/2))/(dx) = (1/2) x^((1/2)-1) = (1/2) x^(-1/2) = 1/(2 x^(1/2)) = 1/(2 sqrt(x)).
There is a subtle shift in meaning in the use of t. If you say "after t seconds", t is a dimensionless quantity, such as 169. Also in the formula V = 4 sqrt(t) cm3, t is apparently dimensionless. But if you say "t = 169 seconds", t has dimension time, measured in the unit of seconds, and also expressing speed of change of V as (dV)/(dt) presupposes that t has dimension time. But you can't mix formulas in which t is dimensionless with formulas in which t is dimensioned.
Below I treat t as being dimensionless. So where t is supposed to stand for time I write "t seconds" instead of just "t".
Then (dV)/(d(t seconds)) = (d 4 sqrt(t))/(dt) cm3/s = 4 (d sqrt(t))/(dt) cm3/s = 4 / (2 sqrt(t)) cm3/s = 2 / (sqrt(t)) cm3/s.
Plugging in t = 169 gives 2/13 cm3/s.</span>
Let
A------------> <span>number of children
B------------> </span><span>number of adults
we know that
0.40A+0.70B=5.90--------------------------> equation 1
A+B=11------------> A=11-B----------------> equation 2
using a graph tool------------> to resolve the equations system
see the attached figure
the solution is
A=6
B=5
the answer is
A is bigger</span>