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Semmy [17]
3 years ago
11

I need to find the area of the triangle TYY

Mathematics
1 answer:
Rufina [12.5K]3 years ago
8 0

Answer:

20cm Squared

Step-by-step explanation:

Area of a Triangle = Base X Hight divided by 2

= 5 X 8 Divided by 2

= 40 Divided by 2

= 20cm Squared

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I was expecting a choice that said A(1,4) is in the first quadrant so 90 degrees clockwise is fourth quadrant.  For perpendicularity we reverse the coordinates, negating one of them.  For the fourth quadrant, it must be the y coordinate that's negative.  We end up at A'(4,-1).

The answer is the second choice:  create a circle with the center at the origin.  The image of A' will be on the circle, 90 degrees clockwise from A.

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can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylind
shutvik [7]

the new radius be to meet the client's need is 4.9 cm .

<u>Step-by-step explanation:</u>

Here we have , can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's clients needs a cylindrical can that has the same volume but is 15 cm tall. We need to find What must the new radius be to meet the client's need . Let's find out:

Let we have two cylinders of volume V_1 , V_2 with parameters as follows :

r_1=6cm\\h_1=10cm\\r_2=?\\h_2=15cm

We know that volume of cylinder is \pi r^2h , According to question volume of both cylinder is equal i.e

⇒ V_1=V_2

⇒ \pi (r_1)^2h_1= \pi (r_2)^2h_2

⇒ (r_1)^2h_1= (r_2)^2h_2

⇒ \frac{(r_1)^2h_1}{h_2}= (r_2)^2

⇒ (r_2) =\sqrt{ \frac{(r_1)^2h_1}{h_2}}                   Putting all values

⇒ (r_2) =\sqrt{ \frac{(6)^2(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{36(10)}{15}}

⇒ (r_2) =\sqrt{ \frac{360}{15}}

⇒ (r_2) =\sqrt{24}

⇒ (r_2) =4.9cm

Therefore , the new radius be to meet the client's need is 4.9 cm .

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