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3 years ago

I need to find the area of the triangle TYY

Mathematics

1 answer:

Rufina [12.5K]3 years ago

8 0

Answer:

20cm Squared

Step-by-step explanation:

Area of a Triangle = Base X Hight divided by 2

= 5 X 8 Divided by 2

= 40 Divided by 2

= 20cm Squared

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I need to distribute 5(y+3)=35

Anit [1.1K]

Answer: y= 4

Good luck !

7 0

3 years ago

While Leo was visiting his sister in Ashland, he bought a surfboard that was marked down 40% from an original price of $521.28.

katrin2010 [14]

Answer:

$344.04

Step-by-step explanation:

The markdown multiplies the price by (1 -40%) = 0.60.

The tax multiplies the price by (1 +10%) = 1.10.

The two factors applied to the price make the final price be ...

$521.28·0.60·1.10 = $344.04

The total cost of the surfboard was $344.04.

5 1

2 years ago

What are the mean and mode of the following data set? 59 16 57 46 58 21 36 41 23 64 20 66 40 51 28 46 a. mean: 43.5, mode: 46 b.

Dvinal [7]

Answer:

$\boxed{ \bold{ { \boxed{ \sf{mean \: = \: 42 \: , \: mode = 46}}}}}$

Option B is the correct option.

Step-by-step explanation:

Given data:

59 , 16 , 57 , 46 , 58 , 21 , 36 , 41 , 23 , 64 , 20 , 66 , 40 , 51 , 28 , 46

Σx ( sum of the items ) = 672

N ( total number of items ) = 16

Finding the mean

$\boxed{ \sf{mean = \frac{sum \: of \: the \: items}{total \: number \: of \: items}}}$

$\longrightarrow{ \sf{ \frac{672}{16} }}$

$\longrightarrow{ \sf{42}}$

Mean = 42

Finding the mode

In the given data , 46 has the highest frequency.

So, mode = 46

Hope I helped!

Best regards! :D

6 0

3 years ago

3. At San Antonio Middle School, 3 out of 7 students said they would vote in the Student Council election. If there are 350 stud

Alex787 [66]

Answer:

150 students

Step-by-step explanation:

3/7 × 350 = 150

7 0

4 years ago

Find the maximum rate of change of f(x, y) = <img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-%20xe%5E%7B2y%7D" id="TexFormula1"

astraxan [27]

The maximum rate of change occurs in the direction of the gradient vector at the given point, with magnitude equal to the norm of the gradient at that point.

$f(x,y) = x^2 - xe^{2y} \implies \nabla f(x,y) = \left\langle 2x - e^{2y}, -2xe^{2y}\right\rangle \\\\ \implies \nabla f(2,0) = \left\langle 3, -4 \right\rangle \\\\ \implies \left\|\nabla f(2,0)\right\| = \sqrt{3^2 + (-4)^2} = \boxed{5}$

3 0

2 years ago