Answer with Step-by-step explanation:
We are given that
Height (in feet) of ball
a.We have to find the average velocity for the time period t=2 and lasting
(i) 0.5 s
Therefore, t=2+0.5=2.5 s
Average of function on interval [a,b]=f'(c)=
Using the formula
Average velocity on interval [2,2.5]=
(ii) 0.1 s
t=2+0.1=2.1 s
Average velocity on interval [2,2.1]=
(iii) 0.05 s
t=2+0.05=2.05 s
Average velocity on interval [2,2.05]=
(iv) 0.01 s
t=2+0.01=2.01 s
Average velocity on interval [2,2.01]=
Average velocity on interval [2,2.01]=
(b) t=2 s
We have to find the instantaneous velocity at t=2 s
Instantaneous velocity=
Using the formula
Substitute t=2
Instantaneous velocity at t=2 s
v(2)=36-32(2)=-28 ft/s
The answer is 17 and 9
Because 13-4=9 13+4=17
The <u>correct answer</u> is:
0.872.
Explanation:
The correlation coefficient of a regression line is a measure of how closely the line fits our data. Negative correlation coefficients represent decreasing lines; positive correlation coefficients represent increasing lines.
The closer a correlation coefficient is to +1 or -1, the better the fit; a perfect positive fit is r=1 and a perfect negative fit is r=-1.
We can see in the graph that the line is very close to our data, so it is a pretty good fit.
The line is increasing; this means we want a correlation coefficient that is close to 1.
The best choice is 0.872.
Answer:
the answer is B good luck