Write balanced molecular, ionic, and net ionic equations<span> (NIE) for each of the ... </span>3.Mg(OH)2(aq) +. 2HCl(aq). →. MgCl2(aq). +. 2H2O(l). Ionic Equation: Mg2+(aq). + ... 2-(aq). +. Ca2+(aq). →. Ca(C2O4)(s). 5. 2(NH4)3PO4(aq) +. 3Zn(NO3)2(aq) → ... 2-(aq<span>). →. MgCrO4(s). 9. </span>2FeCl3(aq<span>). +. </span>3Mg<span>(s). →. </span>3MgCl2(aq<span>) +. </span>2Fe<span>(s).</span>
Answer:
Partial pressure Ne = 340 Torr
Option B
Explanation:
Gases contained in the vessel:
N₂, Ar, He, Ne
One of Dalton's law for gases determine this:
In a mixture of gases contained in a vessel, total pressure of the system must be the sum of partial pressure of each gas.
Total pressure = 1100 Torr
Let's replace:
Partial pressure N₂ + Partial pressure Ar + Partial pressure He + Partial pressure Ne = 1100 Torr
Partial pressure Ne = 1100 Torr - Partial pressure N₂ - Partial pressure Ar -Partial pressure He
Partial pressure Ne = 1100 Torr - 110 Torr - 250 Torr - 400 Torr
Partial pressure Ne = 340 Torr
Answer:
801 g
Explanation:
From the question given above, the following data were obtained:
Number of mole of Ba₃(PO₄)₂ = 1.33 moles
Mass of Ba₃(PO₄)₂ =?
Next, we shall determine the molar mass of Ba₃(PO₄)₂. This can be obtained as follow:
Molar mass of Ba₃(PO₄)₂ = (137.3×3) + 2[31 + (4×16)]
= 411.9 + 2[31 + 64]
= 411.9 + 2[95]
= 411.9 + 190
Molar mass of Ba₃(PO₄)₂ = 601.9 g/mol
Finally, we shall determine the mass of Ba₃(PO₄)₂. This can be obtained as follow:
Number of mole of Ba₃(PO₄)₂ = 1.33 moles
Molar mass of Ba₃(PO₄)₂ = 601.9 g/mol
Mass of Ba₃(PO₄)₂ =?
Mole = mass /Molar mass
1.33 = Mass of Ba₃(PO₄)₂ / 601.9
Cross multiply
Mass of Ba₃(PO₄)₂ = 1.33 × 601.9
Mass of Ba₃(PO₄)₂ = 801 g
Hey there!
In order to solve for the percentage of water in the compound, you will first need to find its total molar mass. You can do this by adding up the molar masses of each individual element in the compound. Then, you will divide the mass that you find of the water molecules by the total mass to get the percentage.
→ Na₂CO₃ ×<span> 10 H</span>₂<span>O
</span>→ Na₂ = 22.9898 × 2 = 45.9796
→ C = 12.0107
→ O₃ = 15.999 × 3 = 47.997
→ 10 H₂O = 18.015 × 10 = 180.15
Now, just add all of those numbers up for the total molar mass.
→ 45.9796 + 12.0107 + 47.997 + 180.15 = <span>286.1373
</span>
The last step is to divide the molar mass of the 10 water molecules by the total mass.
→ 180.15 ÷ 286.1373 = <span>0.62959 </span>≈ 0.63
Your answer will be about 63%.
Hope this helped you out! :-)
