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beks73 [17]
3 years ago
15

What is the mass of 1.33 moles of Ba3(PO4)2?

Chemistry
1 answer:
Serga [27]3 years ago
8 0

Answer:

801 g

Explanation:

From the question given above, the following data were obtained:

Number of mole of Ba₃(PO₄)₂ = 1.33 moles

Mass of Ba₃(PO₄)₂ =?

Next, we shall determine the molar mass of Ba₃(PO₄)₂. This can be obtained as follow:

Molar mass of Ba₃(PO₄)₂ = (137.3×3) + 2[31 + (4×16)]

= 411.9 + 2[31 + 64]

= 411.9 + 2[95]

= 411.9 + 190

Molar mass of Ba₃(PO₄)₂ = 601.9 g/mol

Finally, we shall determine the mass of Ba₃(PO₄)₂. This can be obtained as follow:

Number of mole of Ba₃(PO₄)₂ = 1.33 moles

Molar mass of Ba₃(PO₄)₂ = 601.9 g/mol

Mass of Ba₃(PO₄)₂ =?

Mole = mass /Molar mass

1.33 = Mass of Ba₃(PO₄)₂ / 601.9

Cross multiply

Mass of Ba₃(PO₄)₂ = 1.33 × 601.9

Mass of Ba₃(PO₄)₂ = 801 g

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calculate the enthalpy change for converting 1.00 mol of liquid water at 100 C to water vapor at 145 degree celsius for water Δ
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A chemist prepares a solution of magnesium chloride MgCl2 by measuring out 49.mg of MgCl2 into a 100.mL volumetric flask and fil
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Answer:  Molarity of Cl^- anions in the chemist's solution is 0.0104 M

Explanation:

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Now put all the given values in the formula of molarity, we get

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As 1 mole of MgCl_2 gives 2 moles of Cl^-

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6 0
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