(2, 8), (2, 5)
Just subtract the numbers that aren't the same.
8 - 5 = 3
So the distance is 3.
Answer:
Step-by-step explanation:
Keywords:
System of equations, variables, cost, tickets, adults, children.
For this case we must solve a system of equations with two variables represented by the tickets of students and adults of a school production.
We define the variables according to the given table:
a: Number of tickets sold to adults
c: Amount of tickets sold to children.
We then have the following system of equations:
A + c = 67
10a + 5c =440
From the first equation, we clear the value of the variable c:
C = 67 - a
Answer:
The value that could replace c in the table is:
C = 67 - a
Option C is the answer!
Hope it helped u if yes mark me BRAINLIEST!
Tysm! Plz
The equations y=55x+50 and y=65x represents Rick's and Betty's trip.
Step-by-step explanation:
Given,
Head start of Rick = 50 miles
Speed of Rick = 55 mph
Let,
x be the number of hours
y be the total miles
Distance covered by Rick in x hours = Speed * Time + Head start
y = 55x + 50
Speed of Betty = 65 mph
Total miles = Speed*Time
y=65x
The equations y=55x+50 and y=65x represents Rick's and Betty's trip.
Keywords: variable, addition
Learn more about variables at:
#LearnwithBrainly
Answer: The system of equations is:
x + 2y + 2 = 4
y - 3z = 9
z = - 2
The solution is: x = -22; y = 15; z = -2;
Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.
The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a <u>Row</u> <u>Echelon</u> <u>Form,</u> which satisfies the following conditions:
- There is a row of all zeros at the bottom of the matrix;
- The first non-zero element of any row is 1, which called leading role;
- The leading row of the first row is to the right of the leading role of the previous row;
For this question, the matrix is a Row Echelon Form and is written as:
![\left[\begin{array}{ccc}1&2&2\\0&1&3\\0&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%262%5C%5C0%261%263%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D)
![\left[\begin{array}{ccc}4\\9\\-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%5C%5C9%5C%5C-2%5Cend%7Barray%7D%5Cright%5D)
or in system form:
x + 2y + 2z = 4
y + 3z = 9
z = -2
Now, to determine the variables:
z = -2
y + 3(-2) = 9
y = 15
x + 30 - 4 = 4
x = - 22
The solution is (-22,15,-2).