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Bess [88]
3 years ago
15

Their approach was inexcusable, and there ware fourteen million, seven thousand, nine hundred twenty in the first wave. In the s

econd wave, there ware only nine hundred thousand eighty-seven how many ware there in all
Mathematics
1 answer:
sdas [7]3 years ago
8 0

Answer:14908007

Step-by-step explanation:just add them both with a calculater

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Find the y value for point F such that DF and EF form a 1:3 ratio. (5 points) Segment DE is shown. D is at negative 3, negative
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I drew the segment and used Pythagorean theorem to solve for its measure. The line formed is the hypotenuse of the imaginary right triangle.

Among the choices only -1.33 and -1.25 is a feasible choice. But I am leaning towards -1.25 as the y-value of point F based on my diagram. Please see attachment.

7 0
3 years ago
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A librarian knows that 45% of the books currently checked out will NOT be returned on the due date. The library has a
malfutka [58]

Answer:

79 books

Step-by-step explanation:

45% books not returned = 55% books will be returned

145 books currently checked out

55% of 145 = 79.75

since you can't return 3/4 of a book, i would round down to 79.

7 0
3 years ago
Solve for each unknown angle measure...
zepelin [54]

Answer:

because l1//l2 => z + 65 = 180

y + 65 = 90

x + 65 = 90

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4 0
3 years ago
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The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
một xe ô tô chuyến trước chở được 3 tấn muối chuyến sau chở nhiều hơn chuyến trước 3 tạ hỏi cả hai chuyến xe đó chở được bao nhi
allochka39001 [22]

Answer:

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Step-by-step explanation:

4 0
2 years ago
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