2. line segment MX is congruent to line segment NX
4. All right angles are congruent
5. line segment QX is congruent to line segment QX
6. ASA Congruence Postulate
7. SAS Congruence Postulate
Hope this helps
Answer:
A. Line, B. Segment D.Ray
Step-by-step explanation:
An object is described to have a zero dimension if it has no height, width or depth.For example a point is 0 dimensional.A two-dimensional object is one whose position can be described using the x-axis and y-axis.This is to say that such objects have both horizontal and vertical displacement component.For example a triangle and plane.A line is 1 dimensional because it has length.A ray is 1 dimensional because it never end on one side.A segment is part of a line hence its 1 dimensional.
The answer to this question is 3
Answer:
Step-by-step explanation:
video store A : 15 + 1.75m
video store B : 7.5 + 2.25m
15 + 1.75m = 7.5 + 2.25m
15 - 7.5 = 2.25m - 1.75m
7.5 = 0.50m
7.5 / 0.50 = m
15 = m <=== there would have to be 15 movie rentals to make them equal
check...
15 + 1.75m 7.50 + 2.25m
15 + 1.75(15) = 7.50 + 2.25(15) =
41.25 41.25
yep...it checks out
Answer:
X = 89.92° or 90.08°
Step-by-step explanation:
The law of sines can be used to find the value of angle X:
sin(X)/26 = sin(67.38°)/24
sin(X) = (26/24)sin(67.38°) ≈ 0.99999901787
There are two values of X that have this sine:
X = arcsin(0.99999901787) ≈ 89.92°
X = 180° -arcsin(0.99999901787) ≈ 90.08°
There are two solutions: X = 89.92° or 90.08°.
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<em>Comment on the problem</em>
We suspect that the angle is supposed to be considered to be 90°. However, the given angle is reported to 2 decimal places, so we figure the requested angle should also be reported to 2 decimal places.
The lengths of the short side that correspond to the above angles are 10.03 and 9.97 units. If the short side were considered to be 10 units, the triangle would be a right triangle, and the larger acute angle would be ...
arcsin(24/26) ≈ 67.38014° . . . . rounds to 67.38°
This points up the difficulty of trying to use the Law of Sines on a triangle that is actually a right triangle.
