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3 years ago

Expand & simplify: (x - 2)(x - 3)

Mathematics

1 answer:

Molodets [167]3 years ago

3 0

Answer:

x^2-5x + 6

Step-by-step explanation:

Here, we want to expand the given expressions

To do this, we multiply each term in the first bracket with each term in the second

We then proceed to collect like terms

We have this as;

x(x-3) - 2(x-3)

= x^2 - 3x -2x + 6

= x^2 -5x + 6

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2х5y-3z-=14 x-2y+=-12 -x+ Зу-2z =13

lukranit [14]

Answer:

x = -34/3, y = 1/3, and z = -35/3

Step-by-step explanation:

2х+5y-3z-=14 let's call this equation 1.

x-2y=-12 let's call this equation 2.

-x+Зу-2z =13 let's call this equation 3.

USING EQUATION 1 AND EQUATION 3.

2х+5y-3z-=14 (EQUATION 1)

-x+Зу-2z =13 (EQUATION 3)

LET'S GET RID OF z, BY MAKING THE COEFFICIENT OF z IN THE TWO EQUATION THE SAME. WE WILL MULTIPLY EQUATION 1 BY 2 AND EQUATION 3 BY 3.

2х+5y-3z-=14 (EQUATION 1) * 2

-x+Зу-2z =13 (EQUATION 3) * 3

4х+10y-6z-=28 let's call this equation 4.

-3x+9у-6z =39 let's call this equation 5.

TO GET RID OF z, WE WILL HAVE TO SUBTRACT EQUATION 5 FROM EQUATION 4 PLEASE TAKE NOTE OF THE SIGNS (-) (+).

4х+10y-6z-=28 (EQUATION 4)

- (-3x+9у-6z =39) (EQUATION 5)

(4x - 3x) + ((+10y) - (+9y)) + ((-6z) - (-6z)) = (28 - 39)

x + y + 0 = -11

x + y = -11 let's call this equation 6.

USING EQUATION 2 AND EQUATION 6, LET'S FIND x AND y.

x-2y=-12 (EQUATION 2)

x + y = -11 (EQUATION 6)

x has the same coefficient in both equations, which is 1. Let's get rid of x so we can find the value of y.

We will subtract equation 6 from equation 2. Take note of the signs.

x-2y=-12 (EQUATION 2)

- (x + y = -11) (EQUATION 6)

(x - x) + ((-2y) - (+y)) = ((-12) - (-11))

0 + -3y = -1

-3y = -1

Divide both sides by -3.

-3y/-3 = -1/-3

y = 1/3

LET'S SUBSTITUTE THE VALUE OF y INTO EQUATION 2 TO GET THE VALUE OF x.

x-2y=-12 (EQUATION 2)

x-2(1/3)=-12

x -2/3 = -12

Add 2/3 to both sides.

x -2/3 + (2/3) = -12 + (2/3)

x + 0 = -34/3

x = -34/3

LET'S SUBSTITUTE THE VALUES OF x and y INTO EQUATION 1 TO GET THE VALUE OF z.

2х+5y-3z-=14 (EQUATION 1)

2(-34/3)+5(1/3)-3z-=14

-68/3 + 5/3 - 3z = 14

-21 - 3z = 14

Add 21 to both sides.

-21 + (21) - 3z = 14 + (21)

0 - 3z = 35

-3z = 35

Divide both sides by -3.

-3z/-3 = 35/-3

z = -35/3 or

Therefore, x = -34/3, y = 1/3, and z = -35/3

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6 0

3 years ago

Which relationship describes angles 1 and 2?

Gwar [14]

Adjacent angles describes the relation there

7 0

3 years ago

Read 2 more answers

In the figure, △ABC is similar to △DEF. what is m∠1

Nady [450]

Answer:

C. 139°

Step-by-step explanation:

Given:

m<A = 62°

m<B = 77°

Required:

Find m<1

Solution:

Since ∆ABC is similar to ∆DEF, therefore:

<A ≅ <D, which means m<D = 62°

<B ≅ <E, which means m<E = 77°

<C ≅ <F

Therefore, based on exterior angle theorem:

m<1 = m<D + m<E

m<1 = 62° + 77° (substitution)

m<1 = 139°

7 0

3 years ago

Which quadrilateral has diagonals that always bisect its angles and also bisect each other? 1) rhombus.2)rectangle.3)parallelogr

Juliette [100K]

The answer is 2. rectangles.
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Write an equation of a line containing the point (-2, 1) and is perpendicular to y= -1/4x-4

frosja888 [35]

the answer should be -4

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